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3 years ago

PLEASE HELP!!!

Mathematics

2 answers:

Irina-Kira [14]3 years ago

6 0

Answer:

D. The solution is (8, 2).

Step-by-step explanation:

x - 2y = 4

5x -3y = 34 Multiply the first equation by 5:

5x - 10y = 20 Subtract:

0 + 7y = 14

y = 2.

Substitute for y in the first equation:

x - 2*2 = 4

x = 4+4 = 8.

Nutka1998 [239]3 years ago

5 0

Answer: D

Step-by-step explanation:

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Which best describes the relationship between the line that passes through the points (-6, 5) and (-

Hatshy [7]

Answer:

Line that passes through the points (-6,5) and (-2,7) is,

y=x/2+8, slope is 1/2

line that passes through the points (4,2) and (6,6) is,

y=2x-6, slope is 2

so, there is no relationship between those two lines,

intersection point is (28/3,38/3)

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3 years ago

she has 6 cherry candies, 3 grape candies, and 3 lime candies. If Charlotte randomly pulls one piece of candy out of the bag, wh

yKpoI14uk [10]

Answer: $\dfrac{1}{2}$

Step-by-step explanation:

We know that probability for any event = $\dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}$

Given : Charlotte has 6 cherry candies, 3 grape candies, and 3 lime candies.

I..e Total pieces of candies she has = 6+3+3= 12

Now , If Charlotte randomly pulls one piece of candy out of the bag, what is the probability that it will be cherry is given by :-

$\text{P(cherry)}=\dfrac{\text{Number of cherries}}{\text{Total candies}}\\\\=\dfrac{6}{12}\\\\=\dfrac{1}{2}$

Hence, the probability that it will be cherry is $\dfrac{1}{2}$ .

7 0

3 years ago

At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?

hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

$d*sin(\theta) = m\lambda$

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle

At the first-order maximum (m=1) at 20.0 degrees we have:

$\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342$

Now, to produce a second-order maximum (m=2) the angle must be:

$sin(\theta) = \frac{\lambda}{d}*m$

$\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}$

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.

I hope it helps you!

6 0

3 years ago

1/(x+4)(x-2)(x-5) excluded values

UNO [17]

Answer:

see explanation

Step-by-step explanation:

The excluded values are any values of x that make the function undefined

Given

$\frac{1}{(x+4)(x-2)(x-5)}$

The denominator of the rational function cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the values that x cannot be.

(x + 4)(x - 2)(x - 5) = 0

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

x - 2 = 0 ⇒ x = 2

x - 5 = 0 ⇒ x = 5

x = - 4, x = 2, x = 5 are the excluded values

4 0

3 years ago

A store sells cans of tomatoes priced as shown.

lesantik [10]

Answer:

The answer is C. 18 ounces

Step-by-step explanation:

You just divide the ounces by the cost and which ever you get lower is the answer

3 0

3 years ago