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olga_2 [115]
3 years ago
11

Solve the equation 15=2+4-d

Mathematics
2 answers:
uysha [10]3 years ago
8 0

Answer:

d=-9

Step-by-step explanation:

weqwewe [10]3 years ago
5 0

4+2=6

6- -9=15 ***If you take 6 and subtract -9, the subtraction and negative signs cancels each other out. This means that its just like adding 9.  

d=-9

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Prove that: [1 + 1/tan²theta] [1 + 1/cot² thata] = 1/(sin²theta - sin⁴theta]
Stels [109]

Step-by-step explanation:

<h3><u>Given :-</u></h3>

[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]

<h3><u>Required To Prove :-</u></h3>

[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)

<h3><u>Proof :-</u></h3>

On taking LHS

[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]

We know that

Tan θ = 1/ Cot θ

and

Cot θ = 1/Tan θ

=> (1+Cot²θ)(1+Tan²θ)

=> (Cosec² θ) (Sec²θ)

Since Cosec²θ - Cot²θ = 1 and

Sec²θ - Tan²θ = 1

=> (1/Sin² θ)(1/Cos² θ)

Since , Cosec θ = 1/Sinθ

and Sec θ = 1/Cosθ

=> 1/(Sin²θ Cos²θ)

We know that Sin²θ+Cos²θ = 1

=> 1/[(Sin²θ)(1-Sin²θ)]

=> 1/(Sin²θ-Sin²θ Sin²θ)

=> 1/(Sin²θ - Sin⁴θ)

=> RHS

=> LHS = RHS

<u>Hence, Proved.</u>

<h3><u>Answer:-</u></h3>

[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)

<h3><u>Used formulae:-</u></h3>

→ Tan θ = 1/ Cot θ

→ Cot θ = 1/Tan θ

→ Cosec θ = 1/Sinθ

→ Sec θ = 1/Cosθ

<h3><u>Used Identities :-</u></h3>

→ Cosec²θ - Cot²θ = 1

→ Sec²θ - Tan²θ = 1

→ Sin²θ+Cos²θ = 1

Hope this helps!!

7 0
3 years ago
The answer to the question below is 8/15 right?
ioda
When you have something like this, to simplify the exponent you multiply them together, so the exponent is 1/3 x 1/5. 
1/3 x 1/5 is 1/15, so the simplified expression is: 
m^{ \frac{1}{15} } 
Hope this helps!
3 0
3 years ago
Read 2 more answers
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STatiana [176]
If you don’t mind...who were you? as in your name?
5 0
3 years ago
A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c
olchik [2.2K]
The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in E^{c}. Find P(E^{c}).

Solution:

Part 1:

E^{c} means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

E^{c}=S-E \\  \\ &#10;E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\  \\ &#10;E^{c}=(4,5,6)

Thus the set compliment of E will contain the elements {4,5,6}.So

E^{c} = {4,5,6}

Part 2)

P(E^{c}) means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

P(E^{c}) = (Number of Elements in E^{c})/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set E^{c} = n(E^{c})=3

So, 

P(E^{c})= \frac{n(E^{c}) }{n(S)} \\  \\ &#10;P(E^{c})= \frac{3}{12} \\  \\ &#10;P(E^{c})= \frac{1}{4}
7 0
3 years ago
Six boys are comparing their heights. Andy is taller than Dan but shorter than Ethan. Bill is taller than Ethan and Frank. Frank
Alexxx [7]

List of boys from tallest to shortest is: Bill, Frank, Ethan, Andy, Dan, Cory

<h3><u>Solution:</u></h3>

Given that Six boys are comparing their heights

The six boys are Andy, Dan, Ethan, Bill, Frank, Cory

To find: List the boys from tallest to shortest

<u><em>Andy is taller than Dan but shorter than Ethan</em></u>

So the arrangement goes like this:

Ethan

Andy

Dan

<u><em>Bill is taller than Ethan and Frank:</em></u>

So Bill is taller than ethan. Thus the arrangement from tall to short is made as:

Bill

Ethan

Andy

Dan

Also bill is taller than frank. So frank can be placed anywhere below bill

But given that Frank is taller than Ethan. So frank can be placed above ethan

Now the arrangement goes like this:

Bill

Frank

Ethan

Andy

Dan

<em><u>Cory is shorter than Dan.</u></em>

So cory can be placed below Dan.

<em><u>Thus final arrangement from tallest to shortest boys are:</u></em>

Bill

Frank

Ethan

Andy

Dan

Cory

5 0
4 years ago
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