Part A:
Given that <span>the mattress is sold for 50% off of the retail price, let the retail price of the mattress be x, then
50% of x = 1200
⇒ 0.5x = 1200
⇒ x = 1200 / 0.5 = 2400
Therefore, </span><span>the retail price of the mattress, before the discount is $2,400.
Part B:
Given that </span><span>the store marks up the retail price to 150% of the wholesale price. Let the whole sale price be p, then
(100% + 150%) of p = 2400
250% of p = 2400
2.5p = 2400
p = 2400 / 2.5 = 960.
Therefore, </span><span>the wholesale price, before the markup was $960</span>
Answer:$29.12
c+0.04c (which can also be written as 1.04c, as they are like terms)
(28)+0.04 x (28)
28 + 1.12
=$29.12
Answer:
The t-distribution is used.
Step-by-step explanation:
When we dont know the standard deviation of the population, we use the t-distribution(t-table).
Otherwise, the z-distribution(z-table) is used.
So the answer to this question is the t-distribution.
3x^2 = 2(x + 4)
3x^2 = 2x + 8
3x^2 - 2x - 8 = 0
(3x + 4)(x - 2) = 0
3x + 4 = 0
3x = -4
x = -4/3
x - 2 = 0
x = 2
solution is : x = -4/3 or x = 2 <==
You figure out the amount of chocolate doughnuts sold by multiplying 2/3 by 7 1/4
first you change 7 1/4 to an improper fraction:
7 1/4= 29/4
now multiply 2/3×29/4 by multiplying the two numerators then putting that over the two denominators multiplied: (2×29)/(3×4)=58/12
now simplify:58/12=4 10/12= 4 5/6
the answer is Stanley's doughnut shop sold
4 5/6 trays of chocolate doughnuts