C = 2πr Divide both sides by 2π
C/2π = r Switch the sides to make it easier to read
r = c / 2π
okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
The domain is the limits of the function. Since time doesnt go negative, start with 0. At time 0, the height is
-16(0)^2 + 144 = 144ft
Then, solve for t to find the upper limit for t, which is when the height is zero (since you're dropping the object).
-16t^2 + 144 = 0
-16t^2 = -144
t^2 = 9
t = sqrt(9)
t = 3
The domain is 0 to 3 seconds.
Answer:
m = 2
n = 4
Step-by-step explanation:
Ok so to solve this, you want to get it so there is only one variable and then solve that equation. To do this, you can start by doing:
3m + n = 10
multiply both sides by 2
6m + 2n = 20
now, in both of your equations you have 2n so you can add the two equations:
6m + 2n = 20
+ 5m - 2n = 2
11m = 22
divide both sides by 11
m = 2.
Now, plug this value into the original equation, 3m + n = 10:
3 * 2 + n = 10
6 + n = 10
subtract 6 from both sides
n = 4