Answer:
Step-by-step explanation:
Midpoint = (x₁+ x₂)/2 , (y₁ +y₂)/2
= [(-1)+(-3))/2] , (-2 + 9)/2
= (-4/2) , (-7/2)
= (-2 , -3.5)
Answer:
0.94
Step-by-step explanation:
The question after this basically is:
<em>"If the applicant passes the "aptitude test for managers", what is the probability that the applicant will succeed in the management position?"</em>
<em />
So,
P(successful if hired) = 60% = 0.6 [let it be P(x)]
P(success at passing the test) = 85% = 0.85 [let it be P(y)]
P(successful and pass the test) = P(x) + P(y) -[P(x)*P(y)]
So,
P(successful and pass the test) = 0.6 + 0.85 - (0.6*0.85) = 0.94 (94%)
Answer:
The Highest common factor of 120,140,180 is ( HCF) = 20
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given numbers 120,140,180
120 = 60 × 2
= 30 × 2× 2
= 15 × 2×2×2
= 5×3× 2×2×2
140 = 70 × 2
= 10 × 7× 2
= 5× 2× 7× 2
180 = 90 × 2
= 30×3×2
= 5 × 6 × 3× 2
= 5 × 2× 3× 2 × 3
The Highest common factor of 120,140,180 is 5 ×2×2 = 20
Let X be a random variable representing the mean reading speed of a sample of second grade students in the city.
P(X > 96) = 1 - P(X ≤ 96) = 1 - P(X ≤ (96 - 92)/(10/sqrt(28)) = 1 - P(X ≤ 2.117) = 1 - 0.98285 = 0.01715
Required probablility = 0.01715
Since 3*5=15, then the answer to 3.7*5.1 should be close to that same value. But if you were solving it by hand, and accidentally wrote the answer as 1.887 or 188.7. Estimating helps you know that you placed the decimal in the wrong area, Since the number isn't close to 15.3.7*5.1+18.87
