Show all work to identify the asymptotes and zero of the function f of x equals 5 x over quantity x squared minus 25.
1 answer:
Answer:
- asymptotes: x = -5, x = 5
- zero: x = 0
Step-by-step explanation:
The function of interest is ...
The asymptotes are found where the denominator is zero. It will be zero when either factor is zero, so at x = 5 and x = -5
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The zeros are found where the numerator is zero. It will be zero for x = 0.
The asymptotes are x=-5, x=5; the zero is x=0.
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Answer:
ST = 12.2
Step-by-step explanation:
See the attached diagram of the triangle.
Here, Δ RST, Δ RSV and Δ STV all are right triangles.
If we assume that, ST = x and SR = y, then
From Δ RSV and Δ STV we get,
SV² = RS² - RV² = ST² - VT²
⇒ y² - 4.2² = x² - 10.3²
⇒ x² - y² = 88.45 .......... (1)
Now, from Δ RST, we have
ST² + SR² = RT²
⇒ x² + y² = (10.3 + 4.2)² = 210.25 .............. (2)
Now, adding equations (1) and (2) we get,
2x² = 298.7
⇒ x² = 149.35
⇒ x = 12.2 (Rounded to the nearest tenth}
So, ST = 12.2 (Answer)
