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rodikova [14]
3 years ago
10

Solve the inequality X+8>5

Mathematics
1 answer:
Alex777 [14]3 years ago
5 0

Answer:

(

−

3

,

∞

)

Step-by-step explanation:

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Suppose n represents an even number for a simplified expression that represents the product of the next two even numbers
Digiron [165]
N+1 x n+2 = whatever that first part means
3 0
3 years ago
Read 2 more answers
Question<br> (X-5y/y3)-1=
Ilia_Sergeevich [38]

Answer:

x  = y^3+5y

Step-by-step explanation:

Complete question

\frac{x - 5y}{y^3} - 1=0\\

Required

Solve for x

We have:

\frac{x - 5y}{y^3} - 1=0

Collect like terms

\frac{x - 5y}{y^3} = 1

Multiply through by y^3

x - 5y = y^3

Make x the subject

x  = y^3+5y

8 0
2 years ago
The hourly wage increase each employee receives each year depends on their number of years of service. Every three years of serv
slava [35]

Answer:

<h2>bhlhgewafhjffdgnhgreesdbjit<u>bbbbhbfghjkkbiiuu</u><u>h</u><u>h</u><u>h</u></h2>
8 0
3 years ago
During the school year, a bus driver made 7 trips to the museum. The distance from the school to the museum is 36 miles. Write a
bagirrra123 [75]

Given:

Number of trips = 7

Distance from the school to the museum = 36 miles.

To find:

Write and solve equations to find how many miles the bus driver drove for the 7 trips.

Solution:

Let x be the number of trips and y be the total number of miles the bus driver drove.

Distance from the school to the museum = 36 miles.

1 trip means from the school to the museum and then from the museum to the school.

Distance covered in 1 trip = 2×36 = 72 miles.

Distance covered in x trips = 72x miles.

y=72x

Substitute x=7 in the above equation to find the total distance the bus driver drove for the 7 trips.

y=72(7)

y=504

Therefore, the bus driver drove 504 miles for the 7 trips.

7 0
3 years ago
Solve x^2=2x+3 by factoring
solong [7]

The solution is x = 1 and x = -3

<em><u>Solution:</u></em>

Given that we have to solve the given equation by factoring

Given equation is:

x^2=2x + 3\\\\x^2 - 2x - 3 = 0

\text{Consider the form } x^2+bx+c

Find a pair of integers whose product is c and and whose sum is b

\text{Compare } x^2-2x-3 = 0 \text{ with } x^2+bx +c\\\\\text{We get } b = -2 \text{ and } c = -3

Now find, a pair of integers whose sum is -2 and product is -3

The integers that satisfies this condition is -1 and 3

When we add - 1 and 3 we get 2

When multiply -1 and 3 we get -3

Thus the pair of integers are -1 and 3

Write the factored form using these integers.

(x-1)(x+3) = 0

The Zero Product Property states that if ab = 0, then either a = 0 or b = 0, or both a and b are 0

Set the factors equal to 0

x - 1 = 0 \text{ and } x + 3 = 0

x = 1 and x = -3

Thus the solution is x = 1 and x = -3

4 0
2 years ago
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