Here's how you simplify those. The rule for raising an exponent to an exponent is that you multiply them. The rule for dividing exponents with the same base is that you subtract the denomonator from the numerator. So let's simplify the first one, which is actually the most confusing.

Multiplying the exponents you get:

Subtracting the denominator from the numerator between the common base of p you get this:

Doing that math gives you

which equals

which is

, or the third one down.
The next one:

simplifies to:

and subtracting the power of the denominator from the power of the numerator gives you:

, which is the last choice.

simplifies to:

which simplifies very nicely to:

, which is the first choice. The other one is found by process of elimination!
Answer:
C = 2 x π x r
Step-by-step explanation:
π = pi 3.14
r = radius
C = circumference
The group paid $ 5250 at first city and $ 6250 at second city
<u>Solution:</u>
Let x = the charge in 1st city before taxes
Let y = the charge in 2nd city before taxes
The hotel charge before tax in the second city was $1000 higher than in the first
Then the charge at the second hotel before tax will be x + 1000
y = x + 1000 ----- eqn 1
The tax in the first city was 8.5% and the tax in the second city was 5.5%
The total hotel tax paid for the two cities was $790
<em><u>Therefore, a equation is framed as:</u></em>
8.5 % of x + 5.5 % of y = 790

0.085x + 0.055y = 790 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
<em><u>Substitute eqn 1 in eqn 2</u></em>
0.085x + 0.055(x + 1000) = 790
0.085x + 0.055x + 55 = 790
0.14x = 790 - 55
0.14x = 735
<h3>x = 5250</h3>
<em><u>Substitute x = 5250 in eqn 1</u></em>
y = 5250 + 1000
<h3>y = 6250</h3>
Thus the group paid $ 5250 at first city and $ 6250 at second city
If every single student met one an another, then you would hear 90 hi's. Since there are 45 different combinations of 2 students meeting another, and since there are 2 hi's each meeting, there would be 90.
I hope that this helps.
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Answer:
$35
Step-by-step explanation:
you take a point off the graph and divide the cost of tickets by the number of tickets.