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3 years ago

Subtract 2x^2-6x+7 from -4x^2 +x-3

1 answer:

4 0

-4x²+x-3 - 2x²-6x+7

First, take away the like terms
-4x² - 2x² = -6x²
x - -6x = 7x
7 - -3 = 10

The answer is:
-6x² + 7x + 10

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The comfy couch furniture store purchased 3 1/3 pages to advertise upcoming sales for the summer. when the store did not receive

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4 years ago

Sally forgot to put her sneakers on before leaving to play at the park. She noticed right away that her feet were becoming very

katrin [286]

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conduction

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3 years ago

A group of consumers were randomly selected and asked whether they were planning to buy a new TV screen within the next year. 56

kodGreya [7K]

Answer:

The approximate probability is 0.1921.

Step-by-step explanation:

The p-value is defined as the probability, [under the null-hypothesis (H₀)], of attaining a result equivalent to or greater than what was the truly observed value of the test statistic.

The hypothesis to test whether the proportion of consumers that plan to buy a new TV screen within the next year is 0.22, is defined as:

H₀: The proportion of consumers that plan to buy a new TV screen within the next year is 0.22, i.e. p = 0.22.

Hₐ: The proportion of consumers that plan to buy a new TV screen within the next year is 0.22, i.e. p > 0.22.

The information provided is:

n = 230

X = 56

Compute the value of sample proportion as follows:

$\hat p=\frac{X}{n}=\frac{56}{230}=0.2435$

Compute the test statistic as follows:

$z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.2435-0.22}{\sqrt{\frac{0.22(1-0.22)}{230}}}=0.87$

The test statistic value is, 0.87.

Compute the p-value as follows:

$p-value=P(Z>0.87)=1-P(Z$

*Use a z-table for the probability.

The p-value of the test is 0.1921.

Thus, the approximate probability of obtaining a sample proportion equal to or larger than the one obtained here is 0.1921.

7 0

3 years ago

What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y = 27 − x^2? show your

LUCKY_DIMON [66]

Answer:

Option B.

Step-by-step explanation:

The given curve is

$y=27-x^2$

We need to find the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve $y=27-x^2$ .

Let the vertex in quadrant I be (x,y), then the vertex in quadrant II is (-x,y) .

Length of the rectangle = 2x

Width of the rectangle = y

Area of a rectangle is

$Area=Length\times width$

$Area=2x\times y$

Substitute the value of y from the given equation.

$Area=2x(27-x^2)$

$A=54x-2x^3$ .... (1)

Differentiate with respect to x.

$\frac{dA}{dx}=54-6x^2$

Equate $\frac{dA}{dx}=0$ , to find the critical points.

$0=54-6x^2$

$6x^2=54$

Divide both sides by 6.

$x^2=9$

$x=\pm 3$

The value of x can not be negative because side length can not be negative.

Substitute x=3 in equation (1).

$A=54(3)-2(3)^3$

$A=162-54$

$A=108$

The area of the largest rectangle is 108 square units.

Therefore, the correct option is B.

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3 years ago

If the sum of -4 and the opposite of a number is multiplied by -3, the result is 6 less than the product of the number and 2. Wh

Igoryamba

-3 (-4 + -x ) = (-4(x) × 2 ) + 6

-3 (-4-x) = (-4x × 2) + 6

-12 + 3x = -8x + 6

3x - 12 = 6 - 8x

add 8x on both sides

11x - 12 = 6

add 12 on both sides

11x = 18

x = 11/18

3 0

3 years ago

Read 2 more answers