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Arlecino [84]
3 years ago
9

the mass of the sun is approximately 1.9885×10^33 grams. select from the drop-down menu to correctly complete the statement. the

mass of the sun is approximately 1.9885×10^30 ____ a. milligrams b. grams c. kilograms
Mathematics
2 answers:
Elanso [62]3 years ago
8 0
I believe the correct answer from the choices listed above is option A. The mass of the sun is approximately 1.9885×10^33 grams which is equivalent to 1.9885×10^30 milligrams. It is because 1 g is equal to 1000 mg. By using this conversion factor, we will obtain such value in units of milligrams.
Advocard [28]3 years ago
8 0

The answer is C. Kilograms. I took the test and milligrams was incorrect. It said kilo was the right answer.

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Somebody who knows how to do this?? plz answer all the questions correctly thanks!
Ksju [112]

Answer:

a) 5/21

b) 4/21

c) 4/21

d) 8/21

Step-by-step explanation:

total number of coins: 21

a) number if dollars: 5

therefore fraction is 5/21

b) number of quarters: 4

therefore fraction is 4/21

c) number of dimes: 4

therefore fraction is 4/21

d) number of nickels: 8

therefore fraction is 8/21

4 0
3 years ago
PLEASE HELP ME, I HAVE NO IDEA!
ivanzaharov [21]

b is 14 for sure

you are welcome to ask me anything



3 0
3 years ago
An individual who has automobile insurance from a certain company is randomly selected. Let X be the number of moving violations
grin007 [14]

Answer:

(X)      0        1          2          3         4

P(X)   0.17   0.23    0.27    0.24    0.09

F(x)    0.17    0.04    0.65    0.91      1      

Step-by-step explanation:  

Given that;

(X)      0        1          2          3         4

P(X)   0.17   0.23    0.27    0.24    0.09

cumulative distribution function can be calculated by;  be cumulatively up the value of p(x) with the values before it;

so

x      F(x)

0     P(X = 0) = 0.17

1       P(X = 0) + P(X = 1) = 0.17 + 0.23 = 0.4

2      P(X = 0) + P(X = 1) + P(X = 2) = 0.17 + 0.23 + 0.27 = 0.65

3      P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.17 + 0.23 + 0.27 + 0.24 = 0.91

4      P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.17 + 0.23 + 0.27 + 0.24 + 0.09 = 1

Therefore, cumulative distribution function f(x) is;

(X)      0        1          2          3         4

P(X)   0.17   0.23    0.27    0.24    0.09

F(x)    0.17    0.04    0.65    0.91      1      

8 0
3 years ago
Find the slope of the line that passes through the points f(4) = 6 and f(-2) = 8.
leonid [27]

Answer:

slope = - \frac{1}{3}

Step-by-step explanation:

given f(4) = 6 and f(- 2) = 8 , then 2 points on the line are

(4, 6 ) and (- 2, 8 )

calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (4, 6 ) and (x₂, y₂ ) = (- 2, 8 )

m = \frac{8-6}{-2-4} = \frac{2}{-6} = - \frac{1}{3}

6 0
2 years ago
Comparing Leaking Pool Problem
Blababa [14]

Answer:

<em>Pool 1 leaks faster than pool 2.</em>

Step-by-step explanation:

<u>Rates of change</u>

The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.

We are given two rates of change for two pools that are leaking. The first one loses 2/3 gallon in 15 minutes, and the other loses 3/4 gallon in 20 minutes.

To compare them, we are required to express time in hours. Recall one hour has 60 minutes, or equivalently, one minute has 1/60 hours. Converting both times, we have:

15 minutes = 15/60 = 1/4 hours

20 minutes = 20/60 = 1/3 hours

Now compute both rates of change:

Pool 1:

\displaystyle ROC_1=\frac{2/3}{1/4}=\frac{8}{3}\approx 2.67\ gal/h

Pool 2:

\displaystyle ROC_2=\frac{3/4}{1/3}=\frac{9}{4}= 2.25\ gal/h

Comparing both ratios, it's clear pool 1 leaks faster than pool 2.

8 0
3 years ago
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