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Alona [7]
3 years ago
11

Help me i am so confused

Mathematics
1 answer:
shusha [124]3 years ago
6 0
1. 50 people
2. 2/5
3. 100 people
4. 102 people
5. 434 people
6. 1116 people
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Complete the patterns 0.03 0.3 3 30 and what is the pattern
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30x 10= 300x 10= 3000. Times by ten
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Which is an equation of a line perpendicular to the line with the equation 5x-4y=8
Andrej [43]

Answer:

In exercises 3 and 4,write an equation of the line that passes through the given point and is parallel to the given line. 3. (1,3); y=2x-5 4. (-2,1); y= -4x+3 *In exercises 5 and 6, determine which of the lines,if any, are parallel or perpendicular. Explain! 5. line a passes through (-2,3) and (1,-1). Line b passes through (-3,1) and (1,4). Line c passes through (0,2) and (3,-2). 6. Line a: y= -4x +7 Line b: x= 4y+2 Line c: -4y+x=3 *In exercises 7 and 8, write an equation of the line that passes through the given point and is perpendicular to the given line. 7. (2,-3); y= 1/3x -5 8.(6,1); y= -3/5x-5 * In exercises 11-13, determine whether the statement is sometimes,always, or never true. Explain your reasoning! 11. A line with a positive slope and a line with a negative slope are parallel. 12. A vertical line is perpendicular to the x-axis. 13. two lines with the same x-intercept are perpendicular.

Step-by-step explanation:

4 0
3 years ago
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Natalia bought 8 glitter wands for 50$
kirza4 [7]

Answer:

Is there more to the question?

4 0
3 years ago
Find the number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4.
Paraphin [41]

As we can see that there are 6 digits in 100,000 and its is the smallest number we can have in 6 digit. So all numbers less than 100,000 will be 1-digit, 2-digits, 3-digits, 4-digits and 5-digits numbers made from 1,2,3,4 with repetitions allowed.

Case 1: All 1 -digit numbers

We will have numbers 1,2,3,4. So total 4 integers for this one

Case2: All 2-digit numbers

We can fill 1 digit place in 4 ways ( can choose any number out of 1,2,3,4). Then again we can fill 2nd digit place in 4 ways ( can choose any number out of 1,2,3,4). So all together we will have 4 × 4 = 16 integers for this one

Case3: All 3-digits numbers

We can fill 1 digit place in 4 ways ( can choose any number out of 1,2,3,4). Then again we can fill 2nd digit place in 4 ways ( can choose any number out of 1,2,3,4). similarly we can fill 3rd digit place in 4 ways (again any number out of 1,2,3,4). So all together we will have 4 × 4 × 4 = 64 integers for this one.

Case4: All 4-digit numbers

Again we can fill 1st digit place in 4 ways, then 2nd digit place in 4 ways, 3rd digit place in 4 ways, 4th digit place in 4 ways. So all together there will be 4 × 4 × 4 × 4 = 256 integers for this one.

Case5: All 5-digit numbers

Again we can fill 1st digit place in 4 ways, then 2nd digit place in 4 ways, 3rd digit place in 4 ways, 4th digit place in 4 ways, 5th digit place also in 4 ways. So all together there will be 4 × 4 × 4 × 4 × 4 = 1024 integers for this one

Adding results of all 5 cases we get,

Total integers = 4 + 16 +64 + 256 + 1024 = 1364 integers.

So thats the final answer

4 0
3 years ago
Read 2 more answers
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