Answer:
$192.50
Step-by-step explanation:
12*38.50=462
7*38.50=269.5
462-269.50=192.50
The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.
That is,
Consider X be the length of the pregnancy
Mean and standard deviation of the length of the pregnancy.
Mean 
Standard deviation \sigma =15
For part (a) , to find the probability of a pregnancy lasting 308 days or longer:
That is, to find 
Using normal distribution,



Thus 
So 




Thus the probability of a pregnancy lasting 308 days or longer is given by 0.00256.
This the answer for part(a): 0.00256
For part(b), to find the length that separates premature babies from those who are not premature.
Given that the length of pregnancy is in the lowest 3%.
The z-value for the lowest of 3% is -1.8808
Then 
This implies 
Thus the babies who are born on or before 238 days are considered to be premature.
Step-by-step explanation:
6 problems= 8 seconds
1 problem = 4/3 seconds
16minutes= 960 seconds
960seconds÷4/3 seconds
=720
I'm not sure but I tried lol
Answer:
A.
(x - 3)(x - 3)
Step-by-step explanation:
x^2 – 6x + 9
What 2 numbers multiply to 9 and add to -6
-3*-3 =9
-3+-3 = -6
(x-3) (x-3)