Question

What is the equation of the following line written in slope-intercept form?

Answer 1

Answer:

Option (2)

Step-by-step explanation:

Let the equation of the line is,

y - y' = m(x - x')

where (x', y') is a point lying on the given line.

And m = slope of the line = $\frac{y_2-y_1}{x_2-x_1}$

Line given in the graph passes through two points (-5, -1) and (-2, -3).

Slope of the line 'm' = $\frac{-3+1}{-2+5}$

                                 = $-\frac{2}{3}$

Therefore, equation of the line passing through(-5, -1) and slope of the line = $-\frac{2}{3}$ will be,

y - (-1) = $-\frac{2}{3}[x-(-5)]$

$y+1=-\frac{2}{3}(x+5)$

$y=-\frac{2}{3}x-\frac{10}{3}-1$

$y=-\frac{2}{3}x-\frac{13}{3}$

Option (2) will be the answer.