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MArishka [77]
3 years ago
15

Is (a-3)(2a^2 + 3a + 3) equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)

Mathematics
2 answers:
Andru [333]3 years ago
6 0

Answer:

  yes

Step-by-step explanation:

(a-3)(2a^2 + 3a + 3) = a(2a^2 + 3a + 3) -3(2a^2 + 3a + 3)

  = 2a^3 +3a^2 +3a -6a^2 -9a -9

  = 2a^3 +a^2(3 -6) +a(3 -9) -9

  = 2a^3 -3a^2 -6a -9

  = 2(a^3 -1.5a^2 -3a -4.5) . . . . the form you're asking about

vovikov84 [41]3 years ago
4 0
<h3>Answer: Yes they are equivalent</h3>

==============================================

Work Shown:

Expand out the first expression to get

(a-3)(2a^2 + 3a + 3)

a(2a^2 + 3a + 3) - 3(2a^2 + 3a + 3)

2a^3 + 3a^2 + 3a - 6a^2 - 9a - 9

2a^3 + (3a^2-6a^2) + (3a-9a) - 9

2a^3 - 3a^2 - 6a - 9

Divide every term by 2 so we can pull out a 2 through the distributive property

2a^3 - 3a^2 - 6a - 9 = 2(a^3 - 1.5a^2 - 3a - 4.5)

This shows that (a-3)(2a^2 + 3a + 3) is equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)

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The rate of change of the height is \frac{1}{9} in/min.

<h3>What is a right circular cylinder?</h3>

A right circular cylinder is a cylinder that has a closed circular surface having two parallel bases on both the ends and whose elements are perpendicular to its base. It is also called a right cylinder.

Volume of the cylinder = \pi r^{2}h

Rate of change of height is  \frac{dh}{dt} = ?

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Since r does not change with time, then r is a constant, so,

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Differentiate both sides with respect to time t,

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To learn more about right circular cylinder from the given link:

brainly.com/question/2762448

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