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3 years ago

Is (a-3)(2a^2 + 3a + 3) equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)

Mathematics

2 answers:

Andru [333]3 years ago

6 0

Answer:

yes

Step-by-step explanation:

(a-3)(2a^2 + 3a + 3) = a(2a^2 + 3a + 3) -3(2a^2 + 3a + 3)

= 2a^3 +3a^2 +3a -6a^2 -9a -9

= 2a^3 +a^2(3 -6) +a(3 -9) -9

= 2a^3 -3a^2 -6a -9

= 2(a^3 -1.5a^2 -3a -4.5) . . . . the form you're asking about

vovikov84 [41]3 years ago

4 0

<h3>Answer: Yes they are equivalent</h3>

==============================================

Work Shown:

Expand out the first expression to get

(a-3)(2a^2 + 3a + 3)

a(2a^2 + 3a + 3) - 3(2a^2 + 3a + 3)

2a^3 + 3a^2 + 3a - 6a^2 - 9a - 9

2a^3 + (3a^2-6a^2) + (3a-9a) - 9

2a^3 - 3a^2 - 6a - 9

Divide every term by 2 so we can pull out a 2 through the distributive property

2a^3 - 3a^2 - 6a - 9 = 2(a^3 - 1.5a^2 - 3a - 4.5)

This shows that (a-3)(2a^2 + 3a + 3) is equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)

Read more about expressions at:

brainly.com/question/4344214

6 0

2 years ago

Is 0/0x7y³ a positive or negative number

charle [14.2K]

Answer:

A = 0/(0 x 7y³)

Let's see the denominator: 0 x 7y³ = 0

=> Whenever the denominator is 0, A is undefined, neither a positive number or negative number

Hope this helps!

3 0

3 years ago

What do I for for c? PLEASE HELP

ira [324]

Just draw one empty circle for 1 and then a filled circle for -1 so then it's 1-1 which equals 0

5 0

2 years ago

If ABC is 160°, what is DBC?

Monica [59]

The answer should be A 160

5 0

3 years ago

Draw at least six different sized rectangles that have an area of 64 square units

olga_2 [115]

Let

x------> the length of the rectangle

y------> the width of the rectangle

we know that

The area of a rectangle is equal to

$A=x*y$

$A=64\ units^{2}$

$x*y=64$ --------> equation 1

let's assume different values of x to get the different values of y

case 1) For x=64 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/64$

$y=1\ units$

the dimensions of the rectangle are 64 units x 1 unit

see the draw in the attached figure N 1

case 2) For x=32 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/32$

$y=2\ units$

the dimensions of the rectangle are 32 units x 2 units

see the draw in the attached figure N 2

case 3) For x=16 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/16$

$y=4\ units$

the dimensions of the rectangle are 16 units x 4 units

see the draw in the attached figure N 3

case 4) For x=30 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/30$

$y=\frac{32}{15} =2\frac{2}{15} \ units$

the dimensions of the rectangle are 30 units x 2 (2/15) units

see the draw in the attached figure N 4

case 5) For x=40 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/40$

$y=1.60\ units$

the dimensions of the rectangle are 40 units x 1.60 units

see the draw in the attached figure N 5

case 6) For x=60 units

substitute in the equation 1

$x*y=64$

$y=64/x$

$y=64/60$

$y=\frac{16}{15} =1\frac{1}{15} \ units$

the dimensions of the rectangle are 60 units x 1 (1/15) units

see the draw in the attached figure N 6

3 0

3 years ago