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4 years ago

11

In 1967, a 30-second Super Bowl commercial cost $40,000. In 2000, a 30-second commercial cost $1,800,000. What was the percent o

f change in the cost of a commercial?

1 answer:

Akimi4 [234]4 years ago

7 0

It increased by 4500% because 1800000/40000 = 45 or 45.00 and since its a whole number anything to the left of the decimal is multiplies by 100.

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Im having trouble on my math hw mind helping me out ?<br>16+a<4?

Margarita [4]

Answer:

a < -12

Step-by-step explanation:

Move all terms not containing

a

to the right side of the inequality.

a < − 12

<3 Hope this helped

4 0

3 years ago

I do not know how to do this! Please help me!

Andrew [12]

$\qquad\qquad\huge\underline{\boxed{\sf Answer}}$

Perimeter of given figure is equal to :

Perimeter of square - side length + quarter Circumference of the circle

that is :

$\qquad \sf \dashrightarrow \:(10 \times 4) - (5 + 5) + \dfrac{2 \pi r}{4}$

$\qquad \sf \dashrightarrow \:40- 10 + \dfrac{3.14 \times 5}{2}$

$\qquad \sf \dashrightarrow \:30+ \dfrac{15.7}{2}$

$\qquad \sf \dashrightarrow \:30 + 7.85$

$\qquad \sf \dashrightarrow \:37.85 \: \: units$

So, the required perimeter is 37.85 units

6 0

2 years ago

In a shop for every pant there are 3 shirts and for every 9 shirts there are 27 pairs of shoes. Express the ratio of pants to sh

gavmur [86]

Answer:

1 : 3 : 9

Step-by-step explanation:

For every Pant = 3 shirts

If

Pant = x ; shirt = 3x

For :

Every 9 shirts = 27 pairs of shoes

Simplifying further :

1 shirt = 3 pairs of shoes

3 shirts = 3 * 3 = 9 pairs of shoes

Expressing as ratio:

1 Pant = 3 shirts = 9 pairs of shoes

1 : 3 : 9

5 0

3 years ago

Find the exact value of the trigonometric expression.

Dmitrij [34]

$\bf \textit{Half-Angle Identities}
\\\\
sin\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1-cos(\theta)}{2}}
\qquad 
cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}}\\\\
-------------------------------\\\\
\cfrac{1}{12}\cdot 2\implies \cfrac{1}{6}\qquad therefore\qquad \cfrac{\pi }{12}\cdot 2\implies \cfrac{\pi }{6}~thus~ \cfrac{\quad \frac{\pi }{6}\quad }{2}\implies \cfrac{\pi }{12}$

$\bf sec\left( \frac{\pi }{12} \right)\implies sec\left( \cfrac{\frac{\pi }{6}}{2} \right)\implies \cfrac{1}{cos\left( \frac{\frac{\pi }{6}}{2} \right)}\impliedby \textit{now, let's do the bottom}
\\\\\\
cos\left( \cfrac{\frac{\pi }{6}}{2} \right)=\pm\sqrt{\cfrac{1+cos\left( \frac{\pi }{6} \right)}{2}}\implies \pm\sqrt{\cfrac{1+\frac{\sqrt{3}}{2}}{2}}\implies \pm\sqrt{\cfrac{\frac{2+\sqrt{3}}{2}}{2}}$

$\bf \pm \sqrt{\cfrac{2+\sqrt{3}}{4}}\implies \pm\cfrac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}\implies \pm \cfrac{\sqrt{2+\sqrt{3}}}{2}
\\\\\\
therefore\qquad \cfrac{1}{cos\left( \frac{\frac{\pi }{6}}{2} \right)}\implies \cfrac{2}{\sqrt{2+\sqrt{3}}}$

which simplifies thus far to

$\bf \cfrac{2}{\sqrt{2+\sqrt{3}}}\cdot \cfrac{\sqrt{2+\sqrt{3}}}{\sqrt{2+\sqrt{3}}}\implies \cfrac{2\sqrt{2+\sqrt{3}}}{2+\sqrt{3}}\implies \cfrac{2\sqrt{2+\sqrt{3}}}{2+\sqrt{3}}\cdot \stackrel{conjugate}{\cfrac{2-\sqrt{3}}{2-\sqrt{3}}}
\\\\\\
\cfrac{2\sqrt{2+\sqrt{3}}(2-\sqrt{3})}{2^2-(\sqrt{3})^2}\implies \cfrac{2\sqrt{2+\sqrt{3}}(2-\sqrt{3})}{1}$

$\bf 2\sqrt{2+\sqrt{3}}(2-\sqrt{3})\impliedby \stackrel{\textit{keep in mind that}}{(2-\sqrt{3})=(\sqrt{2-\sqrt{3}})(\sqrt{2-\sqrt{3}})}
\\\\\\
2\sqrt{2+\sqrt{3}}\cdot \sqrt{2-\sqrt{3}}\cdot \sqrt{2-\sqrt{3}}
\\\\\\
2\sqrt{(2+\sqrt{3})(2-\sqrt{3})\cdot (2-\sqrt{3})}
\\\\\\
2\sqrt{[2^2-(\sqrt{3})^2]\cdot (2-\sqrt{3})}\implies 2\sqrt{1(2-\sqrt{3})}
\\\\\\
2\sqrt{2-\sqrt{3}}$

7 0

4 years ago

-18y + 7 = -29. What does y equal. (I’m very bad at math)

Olin [163]

Answer:

y=2 (correct if wrong)

Step-by-step explanation:

-18y + 7 = -29

-7 -7

-18y = -36

-18/-18 -36/-18

4 0

3 years ago

Read 2 more answers