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zubka84 [21]
3 years ago
6

Help me with Balloon Mortgages?

Mathematics
1 answer:
Ket [755]3 years ago
7 0
I just answered this question. Here's my answer.

Home price is $245,000. There is no down payment mentioned. 
I understand 20/4 as amortized over 20 years and balloon payment after 4 years.

Total cost would be =  Balloon payment + Total monthly payment 

4 years x 12 months = 48 months
Balloon payment =       216,789.79 x 1 mo =   216,789.79
Total monthly payment = 1,727.11 x 47 mos =  81,174.17

<span>Total cost = 216,789.79 + 81,174.17 = 297,963.96</span>
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Find the next two terms for the following pattern 1, -2, 2, -4, 0
Oxana [17]
After figuring out a common difference in this pattern, we can get further terms in the pattern:
1, -2, 2, -4, 0, -3, -1
5 0
2 years ago
I really need help please.
love history [14]

Answer:

64

Step-by-step explanation:

6 0
3 years ago
Find the area. 7 cm 5 cm 5 cm 22 cm 10 cm 20 cm. HELP PLEASE!!!!​
Sever21 [200]

Answer:

770000

Step-by-step explanation:

im not sure

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2 years ago
John and his friend ordered lunch at a local sandwich shop. They each ordered a soft drink that costs $1.65. John orders a whole
ExtremeBDS [4]

Answer:

a. $12.54 = $ 1.65 + c/2 + c b. $ 7.26

Step-by-step explanation:

a. What equation can you use to find the cost c of a sandwich

Let c be the cost of a whole ham sandwich. Now, the total bill = cost of drinks + cost of half a ham sandwich  + cost of a whole ham sandwich.

total bill = $ 12.54, cost of drinks = $ 1.65, cost of half a ham sandwich = c/2 and cost of a whole ham sandwich = c. So,

$12.54 = $ 1.65 + c/2 + c

b. What is the value of c

We then solve for c in the equation $12.54 = $ 1.65 + c/2 + c

collecting like terms, we have

$12.54 - $ 1.65 = c/2 + c

$ 10.89 = 3c/2

multiplying through by 2, we have

$ 10.89 × 2 = 3c

$ 21.78 = 3c

dividing through by 3, we have

c = $ 21.78/3

= $ 7.26

4 0
2 years ago
One urn contains one blue ball (labeled b1) and three red balls (labeled r1, r2, and r3). a second urn contains two red balls (r
Flura [38]

Answer:

12 possibilities

Step-by-step explanation:

In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.

The same thing occurs in the second urn, as all balls have different labels.

The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).

For the first urn, we have a combination of 4 choose 2:

C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities

For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.

In total we have 6 + 6 = 12 possibilities.

3 0
3 years ago
Read 2 more answers
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