Answer:
I think sentence 3 bc it doesn't really make any sense Ik it's explaining it but it doesnt connect with the whole story as much I think it has to have more details
Answer:
The correct answer is Adaptive differential pulse code modulation
Explanation:
Adaptive differential pulse code modulation (ADPCM) is a variant of differential pulse-code modulation (DPCM) that varies the size of the quantization step, to allow further reduction of the required data bandwidth for a given signal-to-noise ratio. The output data rate can be dynamically adjusted between 16 kbit/s and 64 kbit/s in these applications.
Answer:
<em>C++.</em>
#include <iostream>
using namespace std;
////////////////////////////////////////////////////////////////
int main() {
int weekly_hours = 0;
int hourly_rate;
float gross_pay = 0;
cout<<"Enter weekly hours worked: ";
cin>>weekly_hours;
cout<<"Enter hourly rate: ";
cin>>hourly_rate;
cout<<endl;
////////////////////////////////////////////////
if (weekly_hours > 40) {
gross_pay = (weekly_hours*hourly_rate) + ((weekly_hours*hourly_rate)*0.5);
}
else
gross_pay = weekly_hours*hourly_rate;
cout<<"Weekly gross pay: $"<<gross_pay;
////////////////////////////////////////////////
return 0;
}
Answer:
see explaination
Explanation:
I made use of python program to solve this.
text file name with fun.txt.
6 fun. 3 hello 10 <> 2 25 4 wow!
Program code:
import re
file = open('fun.txt','r') #for reading file
strings="" #declaring empty string
for k in file:
strings=strings+k #all character in file is storing in strings variable for do operations
pattern = '\s' #for pattern \s is for space
result = re.split(pattern, strings) #split the string with space
for k in range(len(result)): #loop through the list of string
if(k%2) == 0: #checking for integer to time of string
p=int(result[k])
print(result[k+1] *p) #print times of the string(k+1)
Check attachment for output
Answer:
A. Lookup
Explanation:
You would use the Lookup field to store a value from another table.
