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Yuliya22 [10]
3 years ago
10

Retraining is required at intervals of ___ or less.

Computers and Technology
1 answer:
loris [4]3 years ago
5 0

Retraining is required at intervals of <u>6 months</u> or less.

A)  6 months

<u>Explanation:</u>

Retraining can be defined as the process of making employees aware of the new technologies, strategies, and getting them a hands-on approach so that they can incorporate them into their allotted work.

For the healthy and smooth functioning of an enterprise, retraining should be done in after short intervals of time like six months.

Retraining ensures that the employees not only are aware of new inventions, but they are also able to follow the trends of the market and retraining also allows them to test their current knowledge and application of acquired skills.

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3 years ago
Create a program that includes a function called toUpperCamelCase that takes a string (consisting of lowercase words and spaces)
astraxan [27]

Answer:

#include<iostream>

using namespace std;

//method to remove the spaces and convert the first character of each word to uppercase

string

toUpperCameICase (string str)

{

string result;

int i, j;

//loop will continue till end

for (i = 0, j = 0; str[i] != '\0'; i++)

{

 if (i == 0)       //condition to convert the first character into uppercase

  {

  if (str[i] >= 'a' && str[i] <= 'z')   //condition for lowercase

  str[i] = str[i] - 32;   //convert to uppercase

  }

if (str[i] == ' ')   //condition for space

  if (str[i + 1] >= 'a' && str[i + 1] <= 'z')   //condition to check whether the character after space is lowercase or not

  str[i + 1] = str[i + 1] - 32;   //convert into uppercase

if (str[i] != ' ')   //condition for non sppace character

  {

  result = result + str[i];   //append the non space character into string

  }

}

//return the string

return (result);

}

//driver program

int main ()

{

string str;

char ch;

//infinite loop

while (1)

{

fflush (stdin);

//cout<< endl;

getline (cin, str);   //read the string

//print the result

//cout<< endl << "Q";

// cin >> ch; //ask user to continue or not

ch = str[0];

if (ch == 'q' || ch == 'Q')   //is user will enter Q then terminatethe loop

  break;

cout << toUpperCameICase (str);

cout << endl;

}

return 0;

}

8 0
3 years ago
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