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lora16 [44]
3 years ago
9

Find the vertex of the parabola y=-x^2-2x-5

Mathematics
1 answer:
Llana [10]3 years ago
6 0
The Vertex is the pinnacle of a given parabola, it is also represented as the maximum or minimum value value.

The Equation given is "<span>y=-x^2-2x-5"

The vertex for this parabola is located at (-1,-4).

-I hope this is the answer you are looking for, feel free to post your questions here on brainly in the future. </span>

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Area of a triangle with points at (-9,5), (6,10), and (2,-10)
Ann [662]
First we are going to draw the triangle using the given coordinates. 
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Distance from point A to point B:
d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}
d_{AB}= \sqrt{(6+9)^2+(10-5)^2}
d_{AB}= \sqrt{(15)^2+(5)^2}
d_{AB}= \sqrt{225+25}
d_{AB}= \sqrt{250}
d_{AB}=15.81

Distance from point A to point C:
d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}
d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}
d_{AC}= \sqrt{11^2+(-15)^2}
d_{AC}= \sqrt{121+225}
d_{AC}= \sqrt{346}
d_{AC}= 18.60

Distance from point B from point C
d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}
d_{BC}= \sqrt{(-4)^2+(-20)^2}
d_{BC}= \sqrt{16+400}
d_{BC}= \sqrt{416}
d_{BC}=20.40

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
s= \frac{AB+AC+BC}{2}
s= \frac{15.81+18.60+20.40}{2}
s= \frac{54.81}{2}
s=27.41

Finally, to find the area of our triangle, we are going to use Heron's formula:
A= \sqrt{s(s-AB)(s-AC)(s-BC)}
A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}
A= \sqrt{27.41(11.6)(8.81)(7.01)}
A=140.13

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0
2 years ago
Can I have some help with this problem
Rufina [12.5K]
Corresponding measures have the same ratio.
.. (x -1)/4 = (2x +1)/10
.. 5(x -1) = 2(2x +1) . . . . . . multiply by 20
.. 5x -5 = 4x +2 . . . . . . . . eliminate parentheses
.. x = 7 . . . . . . . . . . . . . . . add 5 -4x

x = 7
7 0
3 years ago
there are 16 boys and 24 girls in chorus whats the percent of the total number of students in chorus are boys?
Ipatiy [6.2K]
The percent of boys in the class is 40% because 16 + 24 = 40 (the entire amount of kids) 16 / 40 = .4 then move decimal twice to the right for percentage which gives you 40%

The answer is 40%

I hope this helped :)

5 0
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3r2 + 11r + 8<br> Factor completely
crimeas [40]

Answer:

(3r+8)(4+1)

Step-by-step explanation:

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3 years ago
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