Answer:
4/9 = 0.(4)
Step-by-step explanation:
Hi there !
4/9 we can write it like 0.(4) repeating decimal
Good luck !
Step-by-step explanation:
10x² + 11x − 6 = 0
10x² + 15x – 4x – 6 = 0
5x(2x + 3) – 2(2x + 3) = 0
(2x + 3) (5x – 2)
Answer:
- 300 -- venue cost
- 24 -- cost for each couple
- x -- the number of couples
- 24x the cost associated with all couple
- 300+24x -- the total cost for the dance
Step-by-step explanation:
Given the scenario that cost is $300 for the venue and $24 for each couple attending a dance at that venue, you want to know the meaning of the variables and terms in 300 +24x.
<h3>Comparison</h3>
You can compare the terms, coefficients, and variables in the given expression with the parts of the problem statement.
- 300 is a constant term that corresponds to "$300 for a venue rental'
- 24 is a coefficient that corresponds to "$24 for each couple"
- x is a variable representing the number of "couple that attends"
- 24x is a term representing the cost associated with "$24 for each couple that attends"
That is, the cost associated with the number of people attending is $24 times the number of couples: 24x. The expression 300+24x is the total of the fixed venue cost and the per-couple costs
Answer:
34.87% probability that all 5 have a wireless device
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
81% of students own a wireless device.
This means that 
If 5 students are selected at random, what is the probability that all 5 have a wireless device?
This is P(X = 5) when n = 5. So


34.87% probability that all 5 have a wireless device