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klemol [59]
3 years ago
13

What are the different ways to represent compounds? Check all that apply. a structural formula a ball model a space-filling mode

l the Kolbe formula a molecular formula an empirical formula a ball and stick model a cylindric model
Computers and Technology
2 answers:
bagirrra123 [75]3 years ago
7 0

Answer:

Compound can be represented as a molecular formula,empirical formula, structural formula,ball and stick model, space filling model.

Explanation:

Compounds can be represented as a chemical formula and a molecular model.

A chemical formula shows the number of atoms present in a compound. Whereas, the molecular model shows the geometry of a compound.

The chemical formula can be further divided into 3 types:

1)molecular formula: indicates the actual number of atoms in a compound.

2)empirical formula: indicates the relative number of atoms present in a compound.

3)structural formula: is illustrated in the forms of lines which actually shows the bond(such as covalent bond) and also shows how atoms are connected to each other in a molecule.

Molecular model is preferably a better way to represent a molecule. It is categorised into the following:

1)a ball and stick model: its a three dimensional representation of a compound. The atom(s) in a compound is represented by ball while, their chemical bonds are shown by sticks.

2)A space filling model: its a three dimensional structure,it represents the size and shape of the whole molecule,showing relatively how much space each atom in a molecule occupies.

katrin [286]3 years ago
6 0

Answer:

structural formula, space-filling model, molecular formula, empirical formula and ball and stick model.

Explanation:

Chemical compounds are resultants of chemical elements in a reaction. There are several ways of represent a compound, they are;

Structural formula represents chemical compounds in a two dimensional diagram, showing the bonding of the various elements.

Empirical formula gives the relative number of atoms in the compound, while molecular formula shows the actual number of atoms. Space filling, and ball and stick models are three dimensional diagrams describing the relationship between elements represented as balls and bonds as sticks ( for ball and stick model), and the space occupied by individual elements in the compound (space filling).

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In the software development process, which review studies the software design before it is released for coding?
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1. In the software development process, the <u>software requirement</u> review studies the software design before it is released for coding.

2. <u>Audits</u> and walkthroughs are additional types of reviews performed in the software development process.

<h3>What is software development?</h3>

Software development can be defined as a process through which a software application (program) that is used to perform specific tasks on a computer is conceived, designed, developed (programmed), documented, tested and reviewed.

<h3>What is a software review?</h3>

A software review refers to a process that involves the analysis and examination of a software application (program) by a software developer, computers (robots), project personnel, end users, or user representatives for comment or approval on specifications and standards.

<h3>Types of reviews in software design.</h3>

In the software development process, there are three (3) main types of reviews and these include the following:

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Furthermore, the additional types of reviews performed in the software development process are:

  1. Inspection
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Read more on software development here: brainly.com/question/25760458

8 0
3 years ago
Write a Java class with the following methods: getArray(int numStrings) is an instance method that takes command line input (use
mezya [45]

Answer:

Follows are the code to this question:

import java.util.*;//import packae for user-input  

public class Main//defining a class Main

{

public String[] getArray(int numString)//defining a method getArray

{

String[] name=new String[numString];//defining array of String values

Scanner in = new Scanner(System.in);// creating scanner class object for input values from user-end

for(int i=0;i<numString;i++)//defining for loop for input multiple values

{

System.out.print("Enter String Value :");//print message

name[i]=in.nextLine();//input values

}

return name;//return array values

}

public String getLongestString(String[] sArray)//defining a method getLongestString

{

int m=0,mi=0; //defining integer variables

for(int i=0;i<sArray.length;i++)//defining for loop for check the longest value in array

{

if(m<sArray[i].length())//defining if block that checks m varaible value greater then sArray length  

{

m=sArray[i].length();//use m to hold sArray length

mi=i;//use max_index to hold i that is loop value

}

}

return sArray[mi];//return Longest value

}

public static void main(String[] args)//defining main method

{

Main s=new Main();//Creating object of main class    

String[] n;//defining string variable n  

n=s.getArray(5);//use n varaible to call getArray method and store its value

System.out.println("Longest value is: "+s.getLongestString(n));//use print method to call getLongestString method

}

}

Output:

please find attached file.

Explanation:

In the given java program code, inside the main class two method that is "getArray and getLongestString", is defined, in which the "getArray" method uses an integer variable in its parameter and inside the method, an array is defined that use a  scanner class for input array value.

  • In the "getLongestString" pass as a parameter and inside the method, two integer variable "m and mi" is defined that use in the loop to return the longest string value.
  • In the class main method is to define that creates a class object and call the above method and use the print method to return its value.  

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3 years ago
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

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  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

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  or eax,1           ; ZF=0 indicates failure

  jmp done

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  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
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Radda [10]
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