Answer:
rotation 90° CW about the origin we defined
Step-by-step explanation:
The image has the same orientation (clockwise order of vertices) as the pre-image, so an even number of reflections is involved. These cannot be reflections across the x- or y-axes. The longest edge has an east-west orientation in the pre-image and a south-north orientation in the image. Any reflections must have a net effect of a rotation 90° CW.
Equivalently, the image is rotated 90° clockwise from the pre-image.
With a suitable choice of center of rotation, the image can be obtained with a single 90° CW rotation transformation.
If we define the lower left corner of the pre-image as having coordinates (-1, 2), then a 90° CW rotation about (0, 0) will yield the image.
Answer:
b
Step-by-step explanation:
Sample Response:
<em>The linear equations have the same slope, so the rate of change for each is the same. As long as the rate of change is the same, the lines will stay the same distance apart and not intersect.</em>
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Use y=mx+b. This is for slope. If you're given a coordinate such as (3,2) think of "dibble and then shoot". Go right three and up two. Hope this helps :)
Let
x = number of rs 50
y = number of rs 20
z = number of rs 10
Because there are 25 total notes,
x + y + z = 25 (1)
The ratio of rs 50 to rs 20 is 3:5, therefore
x = 0.6y (2)
The total amount is rs 590, therefore
50x + 20y + 10z = 590
or
5x + 2y + z = 59 (3)
Subtract (1) from (3).
4x + y = 34 (4)
Substitute (2) into (4).
4*(0.6y) + y = 34
3.4y = 34
y = 10
From (2), obtain
x = 6
From (1), obtain
z = 25 - 6 - 10 = 9
Answer:
Kaveri has
6 rs 50 notes,
10 rs 20 notes,
9 rs 10 notes.
