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Svetach [21]
4 years ago
5

Can someone plz help me this fast! Thank you

Mathematics
1 answer:
Mrrafil [7]4 years ago
4 0

Answer:

EF= 5 , DF= 6

Step-by-step explanation:

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Which expression is equivalent to 1/2 (2 - 5x + 6)?
Mars2501 [29]
According to your picture, the answer would be -5/4x+2
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2 years ago
WILL GIVE BRAINLIEST PLZZZ NEED HELP
AleksandrR [38]
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3 years ago
Your bank is offering a savings account with a nominal rate of 1.5%, compounded continuously. If you deposit $1,000 in 2010, wha
Anastaziya [24]

Answer:

$1,161.83

1.51%

Step-by-step explanation:

Continuously compounded interest is:

A = Pe^(rt)

where A is the final amount,

P is the initial amount,

r is the rate per time,

and t is time.

Given P = 1000, r = 0.015, and t = 10:

A = 1000e^(0.015 × 10)

A = 1000e^(0.15)

A = 1161.83

The effective annual yield is the annually compounded rate needed to have the same yield after the same time.  For continuously compounded interest, he equation for effective annual yield is:

R = -1 + e^r

R = -1 + e^0.015

R = 0.0151

The effective annual yield is 1.51%.

7 0
4 years ago
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zloy xaker [14]

Answer:

i dont see anything to answer its blank

Step-by-step explanation:

5 0
3 years ago
1 ) During his morning commute to work in rush hour traffic, Justin's average speed was 30 mi/h. During his afternoon commute ba
Hitman42 [59]

Answer:45 mi/h

Step-by-step explanation:

Recall: Speed = distance / time

Let the time taken for the morning journey be t_{1} and the time taken for the afternoon journey be t_{1} ,and the distance covered be d

that means for the first journey,

30 = \frac{d}{t_{1}}

d = 30 t_{1}

Also for the afternoon journey,

d = 60 t_{2}

Equating the two , since the same distance is being covered , we have

30 t_{1} = 60 t_{2}

that is

t_{1} = \frac{60t_{2}}{30}

t_{1} = 2 t_{2}

Also ,

total distance covered = 30 t_{1} + 60 t_{2}

Average speed = total distance / total time

 = 30 t_{1} + 60 t_{2} / t_{1} +t_{2}

  Recall that   t_{1} = 2 t_{2} , substitute this  into the formula for average speed , then we have

Average speed = 30(2t_{2}) +60 t_{2} / 3t_{2}

Average speed = 120t_{2} / 3t_{2}

Therefore :

Average speed = 40 mi/hr

                           

4 0
3 years ago
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