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9966 [12]
3 years ago
13

What are the roots of the function y = 4x2 + 2x - 30?

Mathematics
1 answer:
a_sh-v [17]3 years ago
7 0

Answer:

-3, 5/2

Step-by-step explanation:

What are the roots of the function y = 4x2 + 2x – 30?

To find the roots of the function, set y = 0. The equation is 0 = 4x2 + 2x – 30.

Factor out the GCF of : 2, so the equation becomes 0 = 2(2x2+x-15)

Next, factor the trinomial completely. The equation becomes: 0=2(x+3)(2x-5)

Use the zero product property and set each factor equal to zero and solve.

x+3=0      2x-5 = 0

x = -3, 5/2

The roots of the function are -3, 5/2.

Hope this helped!

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62.5%

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DerKrebs [107]
Anwser:

y = 2x

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3 years ago
Evaluate each of the following to three significant figures, and express each answer in SI units using an appropriate prefix: (a
Softa [21]

Answer:

a). 4.86\times 10^{-15} m

b). 4.21\times 10^{-2} m³

c). 7.00\times 10^{3} N²

Step-by-step explanation:

In this question we have to convert each option into SI units.

a). 4.86(10^{-6})^{2} mm

= 4.86\times (10^{-12})\times (10^{-3} ) m

= 4.86\times 10^{-15} m

b). (348 mm)³

= (348)^{3}\times (10^{-3})^{3} m³

= 42144192\times 10^{-9} m³

= 4.21\times 10^{-2} m³

c). (83700)^{2}\times (10^{-3})^{2} N²

= 700569\times 10^{4}\times 10^{-6} N²

= 7.00\times 10^{9}\times 10^{-6}N^{2}

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7 0
3 years ago
I toss an unfair coin 12 times. This coin is 65% likely to show up heads. Calculate the probability of the following.
mars1129 [50]

Answer:

a. 0.0368

b. 0.99992131

c. 0.2039

d. 0.0048

e. 0.6533

Step-by-step explanation:

Let the probability of obtaining a head be p = 65% = 13/20 = 0.65. The probability of not obtaining a head is q = 1 - p = 1 -13/20 = 7/20 = 0.35

Since this is a binomial probability, we use a binomial probability.

a. The probability of obtaining 11 heads is ¹²C₁₁p¹¹q¹ = 12 × (0.65)¹¹(0.35) = 0.0368

b. Probability of 2 or more heads P(x ≥ 2) is

P(x ≥ 2) = 1 - P(x ≤ 1)

Now P(x ≤ 1) = P(0) + P(1)

= ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹

= (0.65)⁰(0.35)¹² + 12(0.65)¹(0.35)¹¹

= 0.000003379 + 0.00007531

= 0.0007869

P(x ≥ 2) = 1 - P(x ≤ 1)

= 1 - 0.00007869

= 0.99992131

c. The probability of obtaining 7 heads is ¹²C₇p⁷q⁵ = 792(0.65)⁷(0.35)⁵ = 0.2039

d. The probability of obtaining 7 heads is ¹²C₉q⁹p³ = 220(0.65)³(0.35)⁹ = 0.0048

e. Probability of 8 heads or less P(x ≤ 8) = ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹ + ¹²C₂p²q¹⁰ + ¹²C₃p³q⁹ + ¹²C₄p⁴q⁸ + ¹²C₅p⁵q⁷ + ¹²C₆p⁶q⁶ + ¹²C₇p⁷q⁵ + ¹²C₈p⁸q⁴

= = ¹²C₀(0.65)⁰(0.35)¹² + ¹²C₁(0.65)¹(0.35)¹¹ + ¹²C₂(0.65)²(0.35)¹⁰ + ¹²C₃(0.65)³(0.35)⁹ + ¹²C₄(0.65)⁴(0.35)⁸ + ¹²C₅(0.65)⁵(0.35)⁷ + ¹²C₆(0.65)⁶(0.35)⁶ + ¹²C₇(0.65)⁷(0.35)⁵ + ¹²C₈(0.65)⁸(0.35)⁴

= 0.000003379 + 0.00007531 + 0.0007692 + 0.004762 + 0.01990 + 0.05912 + 0.1281 + 0.2039 + 0.2367

= 0.6533

3 0
3 years ago
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