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2 years ago

Wjat is 6.05 in standard form

Mathematics

2 answers:

leva [86]2 years ago

8 0

The standard form is 65

NeTakaya2 years ago

7 0

I think it would be 6 + .0+ .05 = 6.05 but I don’t remember it’s been a little while.

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What are the like terms in the expression below? 3x + 8 + 3y + 8x

Lorico [155]

The like terms would be 3x and 8x

4 0

3 years ago

A school bus has 25 seats, with 5 rows of 5 seats. 15 students from the first grade and 5 students from the second grade travel

kow [346]

Answer:

5P5×20P15

Step-by-step explanation:

A school bus has 25 seats, with 5 rows of 5 seats.

15 students from the first grade and 5 students from the second grade travel in the bus.

second-grade students occupy the first row.

The 5 students of second grade are to be seated in 5 seats,this can be done in:

5P5 ways where P is the permutation

Now 15 students from first grade are to be arranged in remaining 20 seats

This can be done in:

20P15 ways

Hence, total ways student can be seated is:

5P5×20P15

6 0

3 years ago

Jennifer scores a 77 on her algebra 2 test. The mean on the test was 73. The standard deviation on the test was 5. What was her

MA_775_DIABLO [31]

Answer:

0.80

Step-by-step explanation:

The z-score is found from the formula ...

Z = (X -μ)/σ

Z = (77 -73)/5 = 4/5 = 0.80

Jennifer's Z-score was 0.80.

7 0

3 years ago

Use the null hypothesis H0 : μ = 98.6, alternative hypothesis Ha: μ < 98.6, and level of significance α = 0.05. 98 99.6 97.8

andrezito [222]

Answer:

The t-score is -1.8432

Step-by-step explanation:

We are given the following in the question:

98, 99.6, 97.8, 97.6, 98.7, 98.4, 98.9, 97.1, 99.2, 97.4, 99.1, 96.9, 98.8, 99.9, 96.8, 97, 98.7, 97.6, 98.7, 98.2

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1964.4}{20} = 98.22$

Sum of squares of differences = 16.152

$s = \sqrt{\dfrac{16.152}{49}} = 0.922$

Population mean, μ = 98.6

Sample mean, $\bar{x}$ = 98.22

Sample size, n = 20

Sample standard deviation, s = 0.922

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 98.6\\H_A: \mu < 98.6$

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{98.22 - 98.6}{\frac{0.922}{\sqrt{20}} } = -1.8432$

The t-score is -1.8432

7 0

2 years ago

Can someone help me with this task 50PTS!!!!

djverab [1.8K]

Answer:

So sorry if what I solved is wrong .I did my best!

8 0

1 year ago