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Alenkinab [10]
4 years ago
9

How do I solve for y in this equation? 3xy-28=16x

Mathematics
1 answer:
boyakko [2]4 years ago
4 0
3xy-28=16x 

3xy=16x+28    Add \ 28 \ to \ both \ sides 

xy= \dfrac{16x+28}{3}  Divide \ both \ sides \ by \ 3 

xy= \dfrac{4(4x+7)}{3}   Factor \ out \ the \ common \ term \ 4 

<span>y= \dfrac{4(4x+7)}{3x}    </span>Divide \ both \ sides \ by \ x
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MAXImum [283]

Answer:

The three numbers are 29, 31, and 33.

Step-by-step explanation:

Let's imagine that the three consecutive odd integers are 2x−1, 2x+1, and 2x+3. And we are told the sum is 93 right? So, let's equal the three numbers to 93.

2x − 1 + 2x + 1 + 2x + 3 = 93

6x + 3 = 93

     -3     -3

-----------------

6x = 90

/6    /6

----------------

x = 15

Now, plug in x into 2x−1, 2x+1, and 2x+3 to find the three numbers.

2x − 1                   2x + 1                 2x + 3

2(15) - 1                2(15) + 1             2(15) + 3

30 - 1                    30 + 1                 30 + 3

= 29                      = 31                      = 33

6 0
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4 years ago
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lutik1710 [3]

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Polly has a very rain number of dollar bills in her purse and no change.She spends half the money on a scarf and gives $1dollar
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Answer:$26

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4 years ago
What's the answer people. Help
Citrus2011 [14]
This is true <span>in the sense of cardinality. In the same sense that one can say that there are more real numbers than there are rationals (or integers; or natural numbers).</span><span>

source: </span>https://math.stackexchange.com/questions/10333/are-there-many-more-irrational-numbers-than-rational
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