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Vikki [24]
3 years ago
7

Which are the possible side lengths for a triangle?

Mathematics
1 answer:
igomit [66]3 years ago
4 0
The answer is be because when you add 4+8, it equals 12, which is more than 10cm.
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The sum of two numbers is 51 and the greater number is twice the smaller number. Find the numbers. a) set up the variables Let _
Gelneren [198K]

Answer:

  • 34 and 17

Step-by-step explanation:

a) set up the variables

Let x represent the first number Then  y will represent the second number.

b) What is the equation that represents the above situation?

  • x = 2y
  • x + y = 51

c) Solve the equation.

<u>Substitute x in the second equation and solve for y:</u>

  • x + y = 51
  • 2y + y = 51
  • 3y = 51
  • y = 51/3
  • y = 17

<u>Then find x</u>

  • x = 2y = 2*17 = 34
4 0
3 years ago
Read 2 more answers
A(b)(-c), for a=7, b = -2, c= 15
-Dominant- [34]
You just have to plug in the numbers and solve
7(-2)(-15)
7(30)
210


4 0
4 years ago
Read 2 more answers
1) -7v + 4(2 - 5v) = -154
Bad White [126]

Answer:

v=6

Step-by-step explanation:

First let's simplify the equation so it will be easier to PEMDAS the equation later.

-7v+4(2-5v)=-154

-7v+8-20v=-154

-27v+8=-154

Now you must isolate the v variable. You do this by subtracting 8 first and then divide by -27.

-27v+8=-154

-27v=-162

v = 6

5 0
3 years ago
Find the area of the figure. Use 3.14 for A.
Masteriza [31]

Answer:

38.13 m^2

Step-by-step explanation:

the area of a triangle =b*h/2

b=base

h=height

area triangle=(4m*3m)/2=(12m^2)/2=6m^2

the area of a rectangle =b*h

b=base

h=height

area of a rectangle=6m*3m=18m^2

area of a semi circle=(pi*r^2)/2

r=radius

area of a semi circle==(3.14*(3m)^2)/2=14.13m^2

area of the figure=6m^2+18m^2+14.13m^2=38.13m^2

the answer is 38.13m^2

8 0
4 years ago
Angle A is 5x-15. Angle B is 2x+21. Solve for x then find the measure for Angle B
strojnjashka [21]

Answer:

×3-13 ×4-14 ×5-15 ×6-16

4 0
4 years ago
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