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abruzzese [7]
3 years ago
11

Find the perimeter of a semi circle whose diameter is 21cm​

Mathematics
1 answer:
Gala2k [10]3 years ago
4 0

Answer:

<h3>\boxed{ \boxed{ \bold{  \purple{16.485 \: cm}}}}</h3>

Step-by-step explanation:

Diameter ( d ) = 21 cm

Radius is just half of the diameter

Radius ( r ) = \sf{ \frac{21}{2} } = 10.5 cm

Now, let's find the perimeter of a semi - circle :

\sf \frac{1}{2} \pi \: r \:

Plug the values

⇒\sf{ \frac{1}{2}  \times 3.14 \times 10.5}

Calculate

⇒\sf{16.485 \: cm}

Hope I helped!

Best regards!

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What is the y-intercept of the quadratic function f(x) = (x – 8)(x + 3)? (8,0) (0,3) (0,–24) (–5,0)
DiKsa [7]
The correct answer is:  [C]:  " (0, 24) " .
___________________________________________________________

Explanation:
___________________________________________________________

Given the quadratic function:
___________________________________________________________

          →  "  y = (x <span>− 8) (x + 3) "  ;   </span>←  Note:  Replace the "f(x)" with: "y" ; 

→  Find the "y-intercept".
___________________________________________________________

→  Note:  The "y-intercept" is the coordinate of the point(s) of the graph of the equation at which the graph crosses the "x-axis" when "x = 0" . 

   → So;  we set plug in "0" for "x" into our equation; and solve for "y" ; 

          → " y = (x − 8) (x + 3) " ;

          →   y = (0 − 8) (0 + 3)  ; 

          →   y = (-8) * (3)  ;  
 
          →   y = - 24 ; 
___________________________________________________________

So, the "y -intercept" of the <em><u>given</u></em> quadratic function is:
 
the point at which:  "x = 0 ; y = -24 " ;

      →  that is; the point  the coordinates:  " (0, - 24) " ;
___________________________________________________________
  →  which is:  Answer choice:  [C]:  " (0, - 24) " .
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Step-by-step explanation:

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