Answer:
Anatomy supports the theory of evolution because some species share similar physical features that was present in a common ancestor.
An example of shared anatomy is sharks and dolphins. types of analogous structures, such as dolphins and sharks, do not prove species are related, but rather they support the Theory of Evolution by show how species do build up adaptations in order to fit into their environments
Molecular biology because DNA and the genetic code reflect the shared ancestry of life. DNA comparisons can show how related species are.
in recent research is has been shown that the myoglobin and hemoglobin sequences for dozens of mammals, birds, reptiles, amphibians, fish, worms, and molluscs were related.
Structural similarities is when different animals share the same structural similarities. For example the skeletons of turtles, horses, humans, birds, and bats are very similar, despite their t different ways of life and the diversity of their environments.
Explanation:
Malignant tumors are classified according to the type of cells that give rise to them.
Answer: D
Explanation:
The main reason we put telescopes into space is to get around the Earth's atmosphere so that we can get a clearer view of the planets, stars, and galaxies that we are studying. Our atmosphere acts like a protective blanket letting only some light through while blocking others.
Answer:
1/4.
Explanation:
The autosomal dominant trait means that the trait is visible in homozygous dominant and in heterozygous condition. The X linked recessive trait will be pass down from mothers to their sons and daughters will show the trait in homozygous recessive condition only.
The man is achandroplastic dwarf ( Aa) with normal vision (XY ) is married with woman that has normal height (aa) with color blind (XhXh). They have a daughter who is dwarf ( Aa). The probability of being dwarf can be calculated by the cross Aa × aa. The offspring are Aa, Aa, aa, aa. Means 1/2 are the probability of being hetterozygous for achondroplastic . The vision probability is calculated by cross XY and XhXHh. The probability that female is heterozygous is 1/2.
So, the heterozygous probability for both trait is 1/2× 1/2 = 1/4.
