Find all positive and negative integers b such that x^2+bx+22

Mathematics

1 answer:

notsponge [240]3 years ago

3 0

Answer:

you require two numbers m and n such that. x² + bx + c = (x - m)(x - n) where. m + n = b. and. mn = c. In the case where c = 22 and m & n are integers, we have. mn = 22. But, the (positive) …

Step-by-step explanation:

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