Firsly remove the $350
$625-$350=$275
Each person is $6,so divide that from $275
275/6=45R5
The remaining $5 cannot be used to pay for another person,so we leave it as extras.
Therfore,45 people were at the the party.
Answer:
The answer to your question is below
Step-by-step explanation:
Process
To answer if they are right triangles or not use the Pythagorean theorem which states that the square of the hypotenuse equals the sum of the square of the legs.
a) 25² = 20² + 7²
625 = 400 + 49
625 ≠ 449 It is not a right triangle
b) 26² = 24² + 10²
676 = 576 + 100
676 = 676 it is a right triangle
c) 13² = 8² + (√10)²
169 = 64 + 10
169 ≠ 74 it is not a right triangle
d) 52² = 48² + 20²
2704 = 2304 + 400
2704 = 2704 it is a right triangle
No
We know scale factor(k)=y/x
Calculate units as 1 and find k
For left side
![\\ \sf\longmapsto k=\dfrac{5}{3}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20k%3D%5Cdfrac%7B5%7D%7B3%7D)
![\\ \sf\longmapsto k=\dfrac{4}{4}=1](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20k%3D%5Cdfrac%7B4%7D%7B4%7D%3D1)
Hence its not a copy
Answer:
∠1 is 33°
∠2 is 57°
∠3 is 57°
∠4 is 33°
Step-by-step explanation:
First off, we already know that ∠2 is 57° because of alternate interior angles.
Second, it's important to know that rhombus' diagonals bisect each other; meaning they form 90° angles in the intersection. Another cool thing is that the diagonals bisect the existing angles in the rhombus. Therefore, 57° is just half of something.
Then, you basically just do some other pain-in-the-butt things after.
Since that ∠2 is just the bisected half from one existing angle, that means that ∠3 is just the other half; meaning that ∠3 is 57°, as well.
Next is to just find the missing angle ∠1. Since we already know ∠3 is 57°, we can just add that to the 90° that the diagonals formed at the intersection.
57° + 90° = 147°
180° - 147° = 33°
∠1 is 33°
Finally, since that ∠4 is just an alternate interior angle of ∠1, ∠4 is 33°, too.
Answer:
After simplifying we get (x,y) as (1,3).
Step-by-step explanation:
Given:
,
![x-7y=-17](https://tex.z-dn.net/?f=x-7y%3D-17)
We need to use elimination method to solve the and simplify the equations.
Solution;
Let
⇒ equation 1
Also Let
⇒ equation 2
Now by solving the equation we get;
first we will Add equation 2 from equation 1 we get;
![(x+7y)+(4x-7y)=22+(-17)\\\\x+7y+4x-7y=22-17\\\\5x=5](https://tex.z-dn.net/?f=%28x%2B7y%29%2B%284x-7y%29%3D22%2B%28-17%29%5C%5C%5C%5Cx%2B7y%2B4x-7y%3D22-17%5C%5C%5C%5C5x%3D5)
Now Dividing both side by 5 using division property of equality we get;
![\frac{5x}{5}=\frac{5}{5}\\\\x=1](https://tex.z-dn.net/?f=%5Cfrac%7B5x%7D%7B5%7D%3D%5Cfrac%7B5%7D%7B5%7D%5C%5C%5C%5Cx%3D1)
Now Substituting the vale of x in equation 1 we get;
![x+7y=22\\\\1+7y=22](https://tex.z-dn.net/?f=x%2B7y%3D22%5C%5C%5C%5C1%2B7y%3D22)
subtracting both side by 1 using subtraction property of equality we get;
![1+7y-1=22-1\\\\7y=21](https://tex.z-dn.net/?f=1%2B7y-1%3D22-1%5C%5C%5C%5C7y%3D21)
Now Dividing both side by 7 using division property of equality we get;
![\frac{7y}{7}=\frac{21}{7}\\\\y=3](https://tex.z-dn.net/?f=%5Cfrac%7B7y%7D%7B7%7D%3D%5Cfrac%7B21%7D%7B7%7D%5C%5C%5C%5Cy%3D3)
Hence we can say that, After simplifying we get (x,y) as (1,3).