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vlada-n [284]
3 years ago
6

One angle of a linear pair is 4 less than a third of the other angle. Find both angles. Please provide a detailed explanation.

Mathematics
1 answer:
Klio2033 [76]3 years ago
4 0

Answer:

b

Step-by-step explanation:

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Una persona camina 7 kilómetros hacia el norte, después 3 kilómetros hacia el este y, luego, 3 kilómetros hacia el sur. ¿A qué d
qaws [65]

Answer:

La persona está a 5 kilómetros con respecto al punto de partida.

Step-by-step explanation:

Considérese que la dirección norte coincide con el semieje +y y que la dirección este coincide con el semieje +x. A continuación, obtenemos las formas vectoriales equivalentes de cada afirmación:

(i) Una persona camina 7 kilómetros hacia el norte:

\vec r_{1} = 7\,\hat{j}\,[km]

(ii) Después 3 kilómetros hacia el este:

\vec r_{2} = 3\,\hat{i}\,[km]

(iii) Y luego, 3 kilómetros hacia el sur:

\vec r_{3} = -3\,\hat{j}\,[km]

El vector resultante de desplazamiento se construye a partir de la siguiente suma de vectores:

\vec R = \vec r_{1}+\vec r_{2} + \vec r_{3} (1)

\vec R = 3\,\hat{i} + 4\,\hat{j}\,[km]

Asumiendo que la distancia coincide con el desplazamiento resultante, calculamos la distancia con respecto al punto de partida mediante el Teorema de Pitágoras:

\|\vec R\| = \sqrt{3^{2}+4^{2}}

\|\vec R\| = 5\,km

La persona está a 5 kilómetros con respecto al punto de partida.

3 0
3 years ago
Which of the following expressions is equivalent to (x + 5) ^2
Karo-lina-s [1.5K]
(X+5)^2 = x^2 +10x + 25


the expression that is equivalent to

To multiply it we apply FOIL method
Multiply x with x+5 first and then we multiply 5 with x+5






7 0
3 years ago
How to do property eqautionseqautions
Tanya [424]

Answer:


Step-by-step explanation:


4 0
3 years ago
Help ASAP!!!!!! Plzzzzzz
Paraphin [41]

Answer:

2nd option

Step-by-step explanation:

8 0
3 years ago
Which of the following points are more than 5 units from the point P(−2, −2)? Select all that apply. A A (2, 1) B B (4, −1) C C
netineya [11]

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:<span>

<span> |PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}</span></span>


Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.


|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5

|PB|= \sqrt{ (-2-4)^{2} + (-2+1)^{2}}= \sqrt{36+1}= \sqrt{37} \approx 6

|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4

|PD|= \sqrt{ (-2+6)^{2} + (-2+6)^{2}}= \sqrt{16+16}= \sqrt{32}\ \textgreater \  \sqrt{25}=5

|PE|= \sqrt{ (-2+5)^{2} + (-2-1)^{2}}= \sqrt{9+9}= \sqrt{16}=4


Answer: B and D





3 0
3 years ago
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