Question

Find the volume of a right circular cone that has a height of 12.2 cm and a base with a circumference of 18.5 cm. Round your answer to the nearest tenth of a cubic centimeter.

Answer 1

We have been given that a right circular cone has a height of 12.2 cm and a base with a circumference of 18.5 cm. We are asked to find the volume of the cone to nearest tenth.

We know that circumference of circle is equal to $2\pi r$.

$2\pi r=18.5$

$r=\frac{18.5}{2\pi}$

$r=2.944366$

Now we will use volume of the cone formula to solve our given problem.

$V=\frac{1}{3}\pi r^2 h$

$V=\frac{1}{3}\pi (2.944366)^2\cdot (12.2)$

$V=\frac{1}{3}\pi (8.669291141956)\cdot (12.2)$

$V=\frac{1}{3}\pi (105.7653519318632)$

$V=\frac{1}{3}(332.2716526334804752)$

$V=110.7572175$

Upon rounding to nearest tenth, we will get:

$V\approx 110.8$

Therefore, the volume of the given cube would be approximately 110.8 cubic centimeter.