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3 years ago

How can you use equations to solve problems involving area and volume?

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

8 0

Answer:

Step-by-step explanation:

I think you're asking how we use formulas to find areas and volumes.

There's no one area formula; the formula we use to calculate an area depends upon the shape.

For example, the area of a square of side length s is A = s^2.

The area of a triangle with base b and height h is (1/2)*b*h.

Similarly, the choice of formula for the purpose of calculating voume depends upon the shape of the 3-dimensional object.

For example, the volume of a cube with side length s is V = s^3.

The volume of a cylinder with radius r and height h is V = (1/3)πr^2*h.

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madam [21]

Answer:

a.) f(x) = $\frac{1}{30}$ where 90 < x < 120

b.) $\frac{2}{3}$

c.) $\frac{2}{3}$

d.) $\frac{1}{2}$

Step-by-step explanation:

Let

X be a uniform random variable that denotes the actual charging time of battery.

Given that, the actual recharging time required is uniformly distributed between 90 and 120 minutes.

⇒X ≈ ∪ ( 90, 120 )

a.)

Probability density function , f (x) = $\frac{1}{120 - 90} = \frac{1}{30}$ where 90 < x < 120

b.)

P(x < 110) = $\int\limits^{110}_{90} {\frac{1}{30} } \, dx$

= $\frac{1}{30}[x]\limits^{110}_{90} = \frac{1}{30} [ 110 - 90 ] = \frac{1}{30} [ 20] = \frac{2}{3}$

c.)

P(x > 100 ) = $\int\limits^{120}_{100} {\frac{1}{30} } \, dx$

= $\frac{1}{30}[x]\limits^{120}_{100} = \frac{1}{30} [ 120 - 100 ] = \frac{1}{30} [ 20] = \frac{2}{3}$

d.)

P(95 < x< 110) = $\int\limits^{110}_{95} {\frac{1}{30} } \, dx$

= $\frac{1}{30}[x]\limits^{110}_{95} = \frac{1}{30} [ 110 - 95 ] = \frac{1}{30} [ 15] = \frac{1}{2}$

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3 years ago

What is the number 0.00000482 written in scientific notation?

Elena L [17]

Move the decimal so that there is one whole number.

0.00000482 => 4.82

We moved 6 units to the left so:

4.82 * 10^-6

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Answer:

Step-by-step explanation:

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144=-12x-60

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204 = -12x

Lastly, we divide the equation by -12.

204/-12 = -12x/-12

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