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Alisiya [41]
3 years ago
8

The graph of g(x) is the result of translating the graph of f(x) = three units to the left. What is the equation of g(x)?

Mathematics
2 answers:
tamaranim1 [39]3 years ago
8 0
It's B I believe I just took the same test for summer school and put B
jenyasd209 [6]3 years ago
3 0
In the case of exponential functions, the graph is shifted when a constant is added to the exponent of the constant. The original equation, f(x) is:
f(x) = (1/2)ˣ
Now, when horizontal shifting is occurring, the equation is:
y = Cˣ⁺ᵃ
If a is positive, the graph shifts to the lefts and the shift is equal to a units. If a is negative, the graph shifts to the right and the shift is equal to a units. Therefore, to shift the graph 3 units to the left:

g(x) = (1/2)⁽ˣ⁺³⁾
The correct answer is B.
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The equation below represents Function A and the graph represents Function B:
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Answer:

  Slope of Function B = 2 x Slope of Function A.

Step-by-step explanation:

The graph of Function B shows its slope to be 4 units up for 1 unit to the right, so 4.

The equation for Function A shows its slope to be the coefficient of x, so 2.

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4 is 2 times 2, so ...

  the slope of Function B is 2 times the slope of Function A.

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2

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The graph of which function is decreasing over the interval (–4, ∞)?
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a spherical balloon is deflated at a rate of 256pi/3 cm^3/sec. at what rate is the radius of the balloon changing when the radiu
Hunter-Best [27]
What you need to look for is \frac { dr }{ dt } when r=8.

Now:

Volume\quad of\quad a\quad sphere:\\ \\ V=\frac { 4 }{ 3 } \pi { r }^{ 3 }

\therefore \quad \frac { dV }{ dr } =\frac { 4 }{ 3 } \pi \cdot 3{ r }^{ 2 }=4\pi { r }^{ 2 }\\ \\ \therefore \quad \frac { dr }{ dV } =\frac { 1 }{ \frac { dV }{ dr }  } =\frac { 1 }{ 4\pi { r }^{ 2 } }

And:\\ \\ \frac { dV }{ dt } =-\frac { 256\pi  }{ 3 } \\ \\ Therefore:\\ \\ \frac { dr }{ dt } =\frac { dr }{ dV } \cdot \frac { dV }{ dt }

\\ \\ =\frac { 1 }{ 4\pi { r }^{ 2 } } \cdot -\frac { 256\pi  }{ 3 } \\ \\ =-\frac { 256 }{ 12 } \cdot \frac { \pi  }{ \pi  } \cdot \frac { 1 }{ { r }^{ 2 } }

\\ \\ =-\frac { 64 }{ 3{ r }^{ 2 } } \\ \\ When\quad r=8,\\ \\ \frac { dr }{ dt } =-\frac { 64 }{ 3\cdot { 8 }^{ 2 } } =-\frac { 1 }{ 3 } \\ \\ Answer:\quad -\frac { 1 }{ 3 } \quad cm/sec
3 0
4 years ago
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