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rewona [7]
4 years ago
13

What is the answer of 36/25×11

Mathematics
2 answers:
mote1985 [20]4 years ago
6 0

\frac{36}{25}\times \:11

\frac{36}{25} \times \frac{11}{1}

\frac{36\times 11}{25\times 1}

\displaystyle \frac{396}{25}=15.84

Bas_tet [7]4 years ago
3 0

Answer:

15.84

Step-by-step explanation:

36/25 * 11

= (36*11)/ (25*1)

= 396 / 25

= 15.84

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Does the point (6, 0) satisfy the equation y = x + 6?<br>yes or no​
maksim [4K]

Answer:

No.

Step-by-step explanation:

You have to replace the (6,0) with the equation at hand. So, since 6 is in the X spot and 0 is in the Y spot, the equation would then look like 0=6+6. The equation is false as you can see.

5 0
3 years ago
Someone help please i honestly don’t understand
Ivan

Answer:

196 m^2

Step-by-step explanation:

Length of the side of the square = 14 m

area= 14×14 = 196 m^2

hope it helps...

have a great day!!

7 0
3 years ago
What is the correct answer ​ NEED THE ANSWER ASAP
tiny-mole [99]
1 solution


Step by step explanation This is how I got the answer to your question and I gave you the solution I hope this helps you out
8 0
3 years ago
A professional basketball team made 37.9% of its three-point field goals in one season. If 80 three-point field goal attempts ar
kompoz [17]

Answer:

The probability that more than 35 were made is 0.14686.

Step-by-step explanation:

We are given that a professional basketball team made 37.9% of its three-point field goals in one season.

80 three-point field goal attempts are randomly selected from the season.

Let \hat p = <em>sample proportion of three-point field goals made in one season.</em>

The z-score probability distribution for the sample proportion is given by;

                           Z  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} }  ~ N(0,1)

where, p = population proprotion of three-point field goals = 37.9% = 0.379

            n = sample of three-point field goal attempts = 80

            \hat p = sample proportion of three-point field goals = \frac{35}{80} = 0.4375

Now, if 80 three-point field goal attempts are randomly selected from the season, the probability that more than 35 were made is given by = P(\hat p > 0.4375)

P(\hat p > 0.4375) = P( \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} } > \frac{0.4375-0.379}{\sqrt{\frac{0.4375(1-0.4375)}{80}} } ) = P(Z > 1.05) = 1 - P(Z \leq 1.05)

                                                                       = 1 - 0.85314 = <u>0.14686</u>

The above probability is calculated by looking at the value of x = 1.05 in the z table which has an area of 0.85314.

4 0
4 years ago
The ratio of catfish to trout in the local pond is 2 to 5. If there are 300 catfish in the pond, how many trout are there?
kumpel [21]
You would do 300/5 since there are 300 catfish

Then multiply the resulting number (60) by 2

The answer is 120
3 0
4 years ago
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