Question

a right pyramid with a square base has a base edge length of 24 feet and slant height of 20 feet what is the height of the pyramid

Answer 1

Let

l-------> the slant height of the right pyramid

b------> the length side of the square base of the right pyramid

h------> the height of the right pyramid

we know that

Applying the Pythagorean Theorem

$l^{2} =h^{2}+(\frac{b}{2})^{2}$

Solve for h

$h^{2}=l^{2}-(\frac{b}{2})^{2}$

in this problem we have

$l=20\ ft\\\frac{b}{2} =\frac{24}{2} =12\ ft$

Substitute in the formula

$h^{2}=20^{2}-12^{2}$

$h^{2}=256$

$h=16\ ft$

therefore

the answer is

The height of the right pyramid is $16\ ft$

Answer 2

The height of pyramid let being h

h^2 = 20^2 -12^2 

h = sqrt(400-144) = sqrt256 = 16 feet 

hope this will help you