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NeX [460]
3 years ago
12

A network slows down when a network card is locked in a perpetual mode

Computers and Technology
2 answers:
Aliun [14]3 years ago
5 0

What kind of question is this ?

Elena L [17]3 years ago
5 0

i have this same question on my test i need help

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Programming In C:
levacccp [35]

Our function will simply be the inverse of the given one: celsius and kelvin degrees differ by 273.15. You add this number is you compute kelvin from celsius, and you subtract this number if you're going the other way around (which is what we're doing):

#include

double KelvinToCelsius(double valueKelvin ) {

double valueCelsius = 0.0;

valueCelsius = valueKelvin - 273.15;

return valueCelsius ;

}

3 0
3 years ago
(a) How many locations of memory can you address with 12-bit memory address? (b) How many bits are required to address a 2-Mega-
I am Lyosha [343]

Answer:

Follows are the solution to this question:

Explanation:

In point a:

Let,

The address of 1-bit  memory  to add in 2 location:

\to \frac{0}{1}  =2^1  \ (\frac{m}{m}  \ location)

The address of 2-bit  memory to add in 4 location:

\to \frac{\frac{00}{01}}{\frac{10}{11}}  =2^2  \ (\frac{m}{m}  \ location)

similarly,

Complete 'n'-bit memory address' location number is = 2^n.Here, 12-bit memory address, i.e. n = 12, hence the numeral. of the addressable locations of the memory:

= 2^n \\\\ = 2^{12} \\\\ = 4096

In point b:

\to Let \  Mega= 10^6

              =10^3\times 10^3\\\\= 2^{10} \times 2^{10}

So,

\to 2 \ Mega =2 \times 2^{20}

                 = 2^1 \times 2^{20}\\\\= 2^{21}

The memory position for '2^n' could be 'n' m bits'  

It can use 2^{21} bits to address the memory location of 21.  

That is to say, the 2-mega-location memory needs '21' bits.  

Memory Length = 21 bit Address

In point c:

i^{th} element array addresses are given by:

\to address [i] = B+w \times (i-LB)

_{where}, \\\\B = \text {Base  address}\\w= \text{size of the element}\\L B = \text{lower array bound}

\to B=\$ 52\\\to w= 4 byte\\ \to L B= 0\\\to address  = 10

\to address  [10] = \$ 52 + 4 \times (10-0)\\

                       =   \$ 52   + 40 \ bytes\\

1 term is 4 bytes in 'MIPS,' that is:

= \$ 52  + 10 \ words\\\\ = \$ 512

In point d:

\to  base \ address = \$ t 5

When MIPS is 1 word which equals to 32 bit :

In Unicode, its value is = 2 byte

In ASCII code its value is = 1 byte

both sizes are  < 4 byte

Calculating address:

\to address  [5] = \$ t5 + 4 \times (5-0)\\

                     = \$ t5 + 4 \times 5\\ \\ = \$ t5 + 20 \\\\= \$ t5 + 20  \ bytes  \\\\= \$ t5 + 5 \ words  \\\\= \$ t 10  \ words  \\\\

3 0
4 years ago
Which software is used to play, create, and modify audio and video files
larisa86 [58]
The answer your looking for is video editing software

3 0
3 years ago
Read 2 more answers
A (n) ___ system can help a business alleviate the need for multiple information systems.
BigorU [14]

Answer:

Enterprise Resource Planning

Explanation:

ERP

3 0
3 years ago
How can a user access the Mailbox Cleanup tools?
antiseptic1488 [7]

Answer:

Sorry this isn’t an answer but does anyone know of a quizlet for the Microsoft Office course because I can’t find anything anywhere. Help a fellow student out. I need answers.

Explanation:

8 0
3 years ago
Read 2 more answers
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