The equation of line that passes through(5,0) and is perpendicular to the graph of y+ 1=2(x-3) is:
Step-by-step explanation:
Given equation of line is:
The given equation is in point-slope form
So the factor with x will be the slope of the line
Let m1 be the slope of given line
m1 = 2
Let m2 be the slope of second line
As we know that the product of slopes of two perpendicular lines is: -1
So,
The slope intercept form is:
Putting the value of slope
Putting the point in the equation (5,0)
Putting the value of b in the equation
Hence,
The equation of line that passes through(5,0) and is perpendicular to the graph of y+ 1=2(x-3) is:
Keywords: Equation of line, slope
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