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o-na [289]
3 years ago
8

EZ car rental charges $40 a day plus $.25 per mile Ace Rent-A-Car charges $25 a day plus $.45 per mile what number of miles resu

lt of the same cost for one day
Mathematics
1 answer:
anzhelika [568]3 years ago
3 0
'Fatjtwafnzb
&5.75/&5/$5
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Cscx/secx = cotx<br><br> Verify with steps please :)
Dovator [93]
Csc(x) = 1/sin(x)
sec(x) = 1/cos(x)
cot(x) = [1/sin(x)] / [1/cos(x)] 
cot(x) = 1/sin(x) * cos(x)/1
cot(x) = cos(x) / sin(x)
cot(x) = cot(x)
6 0
3 years ago
Explain the distance formula. Than use it to calculate the distance between A(1, 1) and B(7, -7).
Alina [70]
The answer is 10 units.

8 0
3 years ago
Read 2 more answers
How do I solve this?
sasho [114]

Answer:

-m^4n^4

--------------

    108

Step-by-step explanation:

4 0
3 years ago
Data collected over a long period of time show that the length of time x to complete a particular college entrance test is norma
Finger [1]

Using the z-table, the probability that a student taking this test will finish in 100 minutes or less is 0.0824 or 8.24%.

For a normally distributed set of data, given the mean and standard deviation, the probability can be determined by solving the z-score and using the z-table.

First, solve for the z-score using the formula below.

z-score = (x – μ) / σ

where x = individual data value = 100

μ = mean = 125

σ = standard deviation = 18

z-score = (100 – 125) / 18

z-score = (-25) / 18

z-score = -1.39

Find the probability that corresponds to the z-score in the z-table. (see attached images)

-1.39 - (-1.3) : -1.4 - (-1.3) = x - 0.0968 : 0.0808 - 0.0968

-0.09 : -0.1 = x - 0.0968 : -0.016

x - 0.0968 = -0.09(-0.016)/-0.1

x = -0.0144 + 0.0968

x = 0.0824

x = 0.0824

Hence, the probability that a student taking this test will finish in 100 minutes or less is 0.0824 or 8.24%.

Learn more about probability here: brainly.com/question/26822684

#SPJ4

7 0
1 year ago
How many solutions does a system of equations have when solving results in the statement 3 = 5?
blagie [28]
There would be no solutions
8 0
3 years ago
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