Answer:
sorry i do not know can you put the pic bigger
Step-by-step explanation:
It depends on what variable you are tying to solve for first. Say you are trying to solve for x first and then y on the first problem you wrote.
In substitution you solve one of the equations for example with
6x+2y=-10
2x+2y=-10
you solve 2x+2y=-10 for x
2x+2y=-10
-2y = -2y (what you do to one side of the = you do to the other)
2x=-10-2y (to get the variable by its self you divide the # and the variable)
/2=/2 (-10/2=-5 and -2y/2= -y or -1y, they are the same either way)
x=-5-y
now you put that in your original equation that you didn't solve for:
6(-5-y)+2y=-10 solve for that
-30-6y+2y=-10 combine like terms
-30-4y=-10 get the y alone and to do this you first get the -30 away from it
+30=+30
-4y=20 divide the -4 from each side
/-4=/-4 (20/-4=-5)
y=-5
now the equation you previously solved for x can be solved for y.
x=-5-y
x=-5-(-5) a minus parenthesis negative -(- gives you a positive
-5+5=0
x=0
and now we have solved the problem. x=0 and y=-5
false that not true they have all unequal sides
Answer:
Step-by-step explanation:
We will use following steps to measure exactly 4 gallons of water with the help of 5 gallons and 3 gallons empty jugs.
1). Fill 3 gallons jug completely.
2). Pour this 3 gallons of water into 5 gallons jug. Now we have 3 gallons of water in 5 gallons jug and 3 gallons jug empty.
We can add 2 gallons of water in the empty space of 5 gallons jug more.
3). Fill the 3 gallons jug with the water again.
4). Pour this water into 5 gallons jug which can hold 2 gallons of water more.
Now we have 5 gallons of jug filled fully and 1 gallon water remaining in the 3 gallons jug.
5). Empty the 5 gallons jug completely.
6). Pour the remaining 1 gallon of remaining water in 3 gallons jug into 5 gallons jug.
7). Fill the 3 gallons jug completely and pour it into 5 gallon jug.
8). Finally we have 4 gallons of water in the 5 gallons jug.
