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3 years ago

8

Carolyn has $2.55 in her purse in nickels and dimes. The number of nickels is nine less than three times the number of dimes. Fi

nd the number of each type of coin.

1 answer:

Flauer [41]3 years ago

5 0

Hi, the answer is ;

Answer:

12 dimes and 27 nickels

Step-by-step explanation:

.05N + .1d = 2.55

N= 3d - 9

0.05 (3d-9) + 0.1d = 2.55

0.15d - 0.45 + 0.1d = 2.55

0.25d = 2.55 + 0.45

0.25d = 3

D = 12

N = 3 (12) - 9

N = 36 - 9

N = 27

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tatuchka [14]

Simple....

you have:

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leaving you

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still not done....

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3 years ago

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How do I get the answer for 1 1/2 x 3 x 1 1/9

Mekhanik [1.2K]

$\boxed{1 \frac{1}{2}\times 3 \times 1 \frac{1}{9}=5}$

<h2>Explanation:</h2>

in this problem we have the following expression:

$1 \frac{1}{2}\times 3 \times 1 \frac{1}{9}$

So here:

$1 \frac{1}{2} \ and \ 1 \frac{1}{9} \ are \ written \ as \ mixed \ fractions$

Let's convert them as improper fractions:

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Rewriting our expression:

$\frac{3}{2}\times 3 \times \frac{10}{9}=\frac{3\times 3 \times 10}{2\times 9}=\frac{90}{18}=5$

<h2>Learn more:</h2>

Simplify: brainly.com/question/10644722

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3 years ago

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Step-by-step explanation:

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Answer:

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babymother [125]

Call the weights of the two dogs $t$ and $r$ .

We know that Tripp weights 35lbs more than Rico, or:
$t=r+35$

We also know that the total weight of both dogs is 49lbs.:
$t+r=49$

Now, by substitution:
$(r+35)+r=49$
$2r+35=49$
$2r+35-35=49-35$
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$r=\frac{14}{2}$
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Then:
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Tripp weighs 42lbs.

To check our work:
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3 years ago