Find the x-intercept(s) and the coordinates of the vertex for the parabola.
1 answer:
Answer:
see explanation
Step-by-step explanation:
Given
y = x² - 2x - 8
To find the x- intercepts let y = 0 , that is
x² - 2x - 8 = 0 ← in standard form
(x - 4)(x + 2) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 4 = 0 ⇒ x = 4
x + 2 = 0 ⇒ x = - 2
x- intercepts : x = - 2, x = 4
The x- coordinate of the vertex is mid way between the x- intercepts, that is
=
=
= 1
Substitute x = 1 into the equation for corresponding y- coordinate
y = 1² - 2(1) - 8 = 1 - 2 - 8 = - 9
vertex = (1, - 9 )
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The function has a y-intercept at (0, 2). Then the correct options are A, B, and E.
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<h3>What is the maximum and minimum value of the function?</h3>The condition for the maximum will be
f"(x) < 0
The condition for the minimum will be
f"(x) > 0
Consider the inverse function.
f⁻¹(x) = -√(x - 2)
Then the conclusion of the function f(x) = x² + 2 will be
Differentiate the function, then we have
f ' (x) = 2x
Again differentiate, then we have
f" (x) = 2
f" (x) > 0
Then the function has a minimum value at (0, 2)
The function has a y-intercept at (0, 2)
Then the correct options are A, B, and E.
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