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Vladimir79 [104]
3 years ago
7

Paul recently purchased some new clothing for work. He has 4 ties, 7

Mathematics
1 answer:
Elanso [62]3 years ago
4 0
He can make 140 different outfits
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4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
2 years ago
What is the median of 0.8, 1.0, 2.7, 2.8, 3.1, 13.3
tresset_1 [31]

Answer:

2.75

Step-by-step explanation:

<u>Step 1:  Determine the median</u>

0.8, 1.0, 2.7, 2.8, 3.1, 13.3

The median of a set is the middle of the set.  In this instance, we have 6 numbers so we don't have a number directly in the set representing the median.  Instead, we need to find the average or middle between the 3rd and 4th number.  So we take 2.7 and 2.8, add them together to get 5.5 and then we divide by 2 to get 2.75 which is our median.

Answer:  2.75

5 0
1 year ago
Read 2 more answers
Using isosceles triangle theorems solve for x and y
klio [65]
Well lets start by getting y. We already know that all angles of a triangle will equal 180 degrees.
Therefore we know that 65 + 65 + y = 180. To solve for y we just add the two 65's then subtract that from 180
y = 180-130 = 50 Therefore y = 50

Now lets solve for x. We know that since angle B is flat it is equal to 180. The unknown value of angle B = 180 - 65
Therefore that unknown value = 115

As we previously stated all angles of a triangle equal 180. We can now come up with this equation: 115 + x + x = 180
2x = 65
x = 32.5

<span>Hope this helps! If you have anymore questions just ask!</span>
8 0
3 years ago
What is the answer to this proportion question? 5m-3/63 = 9/21
VMariaS [17]

Answer:

Step-by-step explanation:

21(5m - 3) = 63*9

105m - 63 = 567

105m = 630

m = 6

4 0
2 years ago
Read 2 more answers
E=mc square m=3 c=6 solve for E​
just olya [345]

Answer:

E = 3(62)

E = 3(36)

E = 108

6 0
3 years ago
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