Coordinates of point C: (1,-1)
Step-by-step explanation:
In this problem, A, B and C are collinear, and B is between A and C.
The ratio AB : BC is 3 : 1.
This means that we can write the following two equations:
where:
are the coordinates of point A
are the coordinates of point B
are the coordinates of point C
Solving the equation for ,
Solving the equation for ,
So, the coordinates of point C are
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Answer:
Part 1: or
Part 2:
Step-by-step explanation:
To start things off, you must put everything on the opposite side of y so that you only have the y variable left.
In this case, put x onto the other side, making it negative since it's flipped, so you get (since the x is negative you're using subtraction from 11).
Next, divide both sides by 5 to make 5y into y:
Then in this case you turn y=f(x), but the system did it for you, so all you have to put is .
For the second part you must replace x with 2 since you need to find f(2).
Your answer for part 2 is .
Answer:
a) 0.96
b) 0.016
c) 0.018
d) 0.982
e) x = 2
Step-by-step explanation:
We are given with the Probability density function f(x)= 2/x^3 where x > 1.
<em>Firstly we will calculate the general probability that of P(a < X < b) </em>
P(a < X < b) = =
= { Because
}
= =
= =
a) Now P(X < 5) = P(1 < X < 5) {because x > 1 }
Comparing with general probability we get,
P(1 < X < 5) = =
= 0.96 .
b) P(X > 8) = P(8 < X < ∞) = 1/ - 1/∞ = 1/64 - 0 = 0.016
c) P(6 < X < 10) = =
= 0.018 .
d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)
= + (1/
- 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982
e) We have to find x such that P(X < x) = 0.75 ;
⇒ P(1 < X < x) = 0.75
⇒ = 0.75
⇒ = 1 - 0.75 = 0.25
⇒ =
⇒
= 4 ⇒ x =
Therefore, value of x such that P(X < x) = 0.75 is 2.