have an arithmetic sequence here....to find the common difference, subtract the first term from the second term. 13 - 3 = 10...so basically, ur adding 10 to each number to get to the next number.
before we find s5, we r going to find a5...because we need a5 to use in the sum formula.....a5 is the fifth term, and it is 43
sn = (n (a1 + a5) / 2
s5 = (5 (3 + 43) / 2
s5 = (5 (46)) / 2
s5 = 230/2
s5 = 115 <===
or, for this particular problem, s5 is the sum of the first 5 terms.
3 + 13 + 23 + 33 + 43 = 115.....u can do it this way for s5...but if u were asked to find s20, I suggest using the formula.
Answer:
x = 132
Step-by-step explanation:
180 - 48 = 132
372.634 is the answer to this equation
Answer:
![\frac{8}{9}Step-by-step explanation:[tex]\frac{3}{2y-3} + \frac{5}{3z}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B9%7D%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3E%5Btex%5D%5Cfrac%7B3%7D%7B2y-3%7D%20%20%2B%20%5Cfrac%7B5%7D%7B3z%7D)
y = 6, z = 3
Substitute values into the expression:
Simplify both fractions:
Add the fractions:
[tex]\frac{8}{9}
