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stepladder [879]
3 years ago
8

Each of the line segments in the word MATH are numbered in the graph below. Find the slope (as a ratio of rise over run) of each

line segment.
This is very easy, i added multiple choice myself. I am offering 100 points meaning 50 for each answer DON'T WASTE MY POINTS ANSWERS WILL BE REMOVED!!
Do not guess too!

Thanks, Luis

Mathematics
1 answer:
emmasim [6.3K]3 years ago
5 0

Answer/Step-by-step explanation:

7. Line 1 = undefined.

Slope of a vertical line is always undefined. The run is zero as x-coordinate remains the same.

8. Line 2 = \frac{4}{3}

slope = \frac{y_2 - y_1}{x_2 - x_1}

slope = \frac{8 - 4}{-5 -(-8)}

slope = \frac{8 - 4}{-5 + 8}

slope = \frac{4}{3}

9. Line 3 = \frac{4}{3}

slope = \frac{y_2 - y_1}{x_2 - x_1}

slope = \frac{8 - 4}{-2 -(-5)}

slope = \frac{8 - 4}{-2 + 5}

slope = \frac{4}{3}

10. Line 4 = undefined (slope of a vertical line is always undefined)

11. Line 5 = \frac{7}{3}

slope = \frac{y_2 - y_1}{x_2 - x_1}

slope = \frac{8 - 1}{5 - 2}

slope = \frac{7}{3}

12. Line 6 = -\frac{7}{3}

slope = \frac{y_2 - y_1}{x_2 - x_1}

slope = \frac{8 - 1}{5 - 8}

slope = \frac{7}{-3}

slope = -\frac{7}{3}

13. Line 7 = 0

An horizontal line has no rise.

14. Line 8 = 0 (slope of horizontal line is always zero)

15. Line 9 = undefined (slope of a vertical line is always undefined)

16. Line 10 = undefined (slope of a vertical line is always undefined)

17. Line 11 = 0 (slope of horizontal line is always zero)

18. Line 12 = undefined (slope of a vertical line is always undefined)

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Given:

The figure of triangle ABC.

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m\angle B=\sin ^{-1}(\dfrac{m}{n})

To find:

The value of m and n in the given expression.

Solution:

Let h be the height of the triangle ABC.

Area of a triangle is:

Area=\dfrac{1}{2}\times base\times h

Where, b is the base and h is the height of the triangle.

Area=\dfrac{1}{2}\times a\times h

The area of the triangle ABC is D.

D=\dfrac{1}{2}\times a\times h

2D=ah

\dfrac{2D}{a}=h                  ...(i)

In a right angle triangle,

\sin \theta =\dfrac{Perpendicular}{Hypotenuse}

\sin B =\dfrac{h}{c}

\sin B =\dfrac{1}{c}\times \dfrac{2D}{a}              [Using (i)]

\sin B =\dfrac{2D}{ac}

m\angle B =\sin ^{-1}\dfrac{2D}{ac}            ...(ii)

We have,

m\angle B=\sin ^{-1}(\dfrac{m}{n})          ...(iii)

On comparing (ii) and (iii), we get

m=2D

n=ac

Therefore, the required values are m=2D, n=ac.

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