Answer:
Productive; Allocative
Explanation:
The production possibility frontier shows the various combinations of two products that a limited resource.can produce.
So in competitive markets any choice along the PPF shows productive efficiency (where increased production of one good leads to reduced production of the other).
A specific choice by society on the PPF is allocatively efficient (concerned with consumer satisfaction, consumers choose which good will most satisfy them).
Answer:
$112.425
Explanation:
breakeven is
first we need to understand the concept of breakeven:
breakeven in sales makes reference to the amount of revenue in dollars at which a company has a profit of zero ($0.00). covering the underlying fixed expenses of a busines
with this concept we have that :
Total Costs = fixed annual operating cost + variable cost + sold units
Revenue = Total Costs
14.99 * sold units = 75,000 + 4.99 * units
10 * sold units = 75,000
breakeven = 7,500 units
now we can have the breakeven in dollars doing the convertion
breakeven = breakeven in units * prices
breakeven= 7,500 units * $14.99/unit
breakeven = $112,425
Answer:
The highest acceptable manufacturing cost for which Sid's would be willing to produce the cover is $19.60
Explanation:
The computation of the highest acceptable manufacturing cost is shown below:
We know that the market priced at $24.50 and the operating profit is 25% of the cost, we assume the cost is 100 and the selling price equals to
= Cost + operating profit
= 100 + 25% × cost price
= 125
The market price is given for selling price but we have to compute for the cost price
So, the calculation would be
= $24.50 × 100 ÷ 125
= $19.60
First, you have to calculate the amount of tuition when the student reaches age 18. Do this by multiplying $11,000 by 1.07 each year from age 12 until it reaches age 18. Thus, 7 times.
At age 18: 16,508
At age 19: 17,664
At age 20: 18,900
At age 21: 20,223
Then, we use this formula:
A = F { i/{[(1+i)^n] - 1}}
where A is the monthly deposit each year, F is the half amount of the tuition each year illustrated in the first part of this solution, n is the number of years lapsed.
At age 18:
A = (16508/2) { 0.04/{[(1+0.04)^6] - 1}} = $1,244.389 deposit for the 1st year
Ate age 19
A = (17664/2) { 0.04/{[(1+0.04)^7] = $1,118 deposit for the 2nd year
At age 20:
A = (18900/2) { 0.04/{[(1+0.04)^8] = $1,025 deposit for the 3rd year
At age 21:
A = (18900/2) { 0.04/{[(1+0.04)^8] = $955 deposit for the 4th year
