I wrote my decision on a piece of paper.
Answer: 1/70
Step-by-step explanation:
This is a question that can also be interpreted as what is the probability of having the first number of a phone number to be 8 and the last number of the phone number to also be 8. This answer gives the fraction of the phone numbers that starts with 8 and end with 8.
Since three numbers (0,1,2) cannot start a phone number and we are left to pick from 7 numbers,
then the probability of figure "8" starting phone number = 1/7
Since all 10 numbers can possibly end a phone number,
then the probability of having figure "8" as the last digit of a phone number = 1/10
Hence probability of having "8" as the first and last digit of a phone number = fraction of total telephone numbers that begin with digit 8 and end with digit 8 = 1/7 × 1/10 = 1/70.
For
and
to be inversely proportional, there must be some constant
such that
Given that
when
, it follows that
Then when
, we have
Answer:
- 508
Step-by-step explanation:
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 28 and d = - 34 - (- 28) = - 34 + 28 = - 6, thus
= - 28 + (- 6 × 80) = - 28 - 480 = - 508
Answer:
A
Step-by-step explanation:
Given the inequality :
v + 4 > 2 and 8v - 20 < 36
v + 4 > 2
v > 2 - 4
V > - 2
8v - 20 < 36
8v < 36 + 20
8v < 56
v < 56/8
v < 7
Hence,
v > - 2 and v < 7
-2 < v < 7
