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BabaBlast [244]
3 years ago
13

Tracy has 7/8 pounds of butter in her refrigirator. She uses 2/3 of it for cookie batter. How much of the butter did she use?

Mathematics
1 answer:
adelina 88 [10]3 years ago
5 0

Answer:

16/24

Step-by-step explanation:

So you need to get a common denominator before you try to answer the whole question. Turn the denominator into 24. Since you would multiply 8 by 3, multiply the 7 by 3. That would make 21/24. Make the 3 a 24, multiplying it by 8 and doing the same to the 2 making 16/24.

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The ratio of chaperones to students on a field trip is2:7 there are 14 chaperones on the field trip in all how many chaperones a
Luden [163]

Answer:

14 chaperones, 49 students

Step-by-step explanation:

6 0
3 years ago
If m∠NOP = 24 and m∠NOQ = 110, what is m∠POQ? Angle N O Q divided into two unequal angles by ray O P. A. 62 B. 86 C. 134 D. 156
Dmitrij [34]

Answer:

<em>B. 86 degrees</em>

Step-by-step explanation:

Given the following angles:

m∠NOQ = 110

m∠NOP = 24

Using the addition postulate:

m∠NOQ =  m∠NOP + m∠POQ

110 = 24 + m∠POQ

m∠POQ = 110 - 24

m∠POQ = 86

<em>Hence the measure of m∠POQ is 86 degrees</em>

5 0
2 years ago
The ratio of chaperones to students on a field trip to New York City is 2 to 11. If there are 297 students on the trip, how many
Olenka [21]
297/11 = 27

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27x2=54

There are 54 chaperones on the field trip.
7 0
2 years ago
Solve. 54 ÷ (4 – 1)3
pshichka [43]
54 divide 3*3=54 is the answer
3 0
3 years ago
Read 2 more answers
3/8x + 6(x+3) = -5(1/4x - 1) + 6x find the solution pls
umka21 [38]

Answer:

x = -8

Step-by-step explanation:

Solve for x:

(3 x)/8 + 6 (x + 3) = 6 x - 5 (x/4 - 1)

Hint: | Put the fractions in x/4 - 1 over a common denominator.

Put each term in x/4 - 1 over the common denominator 4: x/4 - 1 = x/4 - 4/4:

(3 x)/8 + 6 (x + 3) = 6 x - 5 x/4 - 4/4

Hint: | Combine x/4 - 4/4 into a single fraction.

x/4 - 4/4 = (x - 4)/4:

(3 x)/8 + 6 (x + 3) = 6 x - 5(x - 4)/4

Hint: | Put the fractions in (3 x)/8 + 6 (x + 3) over a common denominator.

Put each term in (3 x)/8 + 6 (x + 3) over the common denominator 8: (3 x)/8 + 6 (x + 3) = (3 x)/8 + (48 (x + 3))/8:

(3 x)/8 + (48 (x + 3))/8 = 6 x - (5 (x - 4))/4

Hint: | Combine (3 x)/8 + (48 (x + 3))/8 into a single fraction.

(3 x)/8 + (48 (x + 3))/8 = (3 x + 48 (x + 3))/8:

(3 x + 48 (x + 3))/8 = 6 x - (5 (x - 4))/4

Hint: | Distribute 48 over x + 3.

48 (x + 3) = 48 x + 144:

(48 x + 144 + 3 x)/8 = 6 x - (5 (x - 4))/4

Hint: | Group like terms in 48 x + 3 x + 144.

Grouping like terms, 48 x + 3 x + 144 = (3 x + 48 x) + 144:

((3 x + 48 x) + 144)/8 = 6 x - (5 (x - 4))/4

Hint: | Add like terms in 3 x + 48 x.

3 x + 48 x = 51 x:

(51 x + 144)/8 = 6 x - (5 (x - 4))/4

Hint: | Put the fractions in 6 x - (5 (x - 4))/4 over a common denominator.

Put each term in 6 x - (5 (x - 4))/4 over the common denominator 4: 6 x - (5 (x - 4))/4 = (24 x)/4 - (5 (x - 4))/4:

(51 x + 144)/8 = (24 x)/4 - (5 (x - 4))/4

Hint: | Combine (24 x)/4 - (5 (x - 4))/4 into a single fraction.

(24 x)/4 - (5 (x - 4))/4 = (24 x - 5 (x - 4))/4:

(51 x + 144)/8 = (24 x - 5 (x - 4))/4

Hint: | Distribute -5 over x - 4.

-5 (x - 4) = 20 - 5 x:

(51 x + 144)/8 = (24 x + 20 - 5 x)/4

Hint: | Combine like terms in 24 x - 5 x + 20.

24 x - 5 x = 19 x:

(51 x + 144)/8 = (19 x + 20)/4

Hint: | Make (51 x + 144)/8 = (19 x + 20)/4 simpler by multiplying both sides by a constant.

Multiply both sides by 8:

(8 (51 x + 144))/8 = (8 (19 x + 20))/4

Hint: | Cancel common terms in the numerator and denominator of (8 (51 x + 144))/8.

(8 (51 x + 144))/8 = 8/8×(51 x + 144) = 51 x + 144:

51 x + 144 = (8 (19 x + 20))/4

Hint: | In (8 (19 x + 20))/4, divide 8 in the numerator by 4 in the denominator.

8/4 = (4×2)/4 = 2:

51 x + 144 = 2 (19 x + 20)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

51 x + 144 = 38 x + 40

Hint: | Move terms with x to the left hand side.

Subtract 38 x from both sides:

(51 x - 38 x) + 144 = (38 x - 38 x) + 40

Hint: | Combine like terms in 51 x - 38 x.

51 x - 38 x = 13 x:

13 x + 144 = (38 x - 38 x) + 40

Hint: | Look for the difference of two identical terms.

38 x - 38 x = 0:

13 x + 144 = 40

Hint: | Isolate terms with x to the left hand side.

Subtract 144 from both sides:

13 x + (144 - 144) = 40 - 144

Hint: | Look for the difference of two identical terms.

144 - 144 = 0:

13 x = 40 - 144

Hint: | Evaluate 40 - 144.

40 - 144 = -104:

13 x = -104

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 13 x = -104 by 13:

(13 x)/13 = (-104)/13

Hint: | Any nonzero number divided by itself is one.

13/13 = 1:

x = (-104)/13

Hint: | Reduce (-104)/13 to lowest terms. Start by finding the GCD of -104 and 13.

The gcd of -104 and 13 is 13, so (-104)/13 = (13 (-8))/(13×1) = 13/13×-8 = -8:

Answer: x = -8

5 0
3 years ago
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