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3 years ago

Use the substitution method to solve these simultaneous equations.

Mathematics

1 answer:

Amanda [17]3 years ago

4 0

Answer:

Step-by-step explanation:

a) 3x+2(41-5x)=33 as y=41-5x is given

3x+82-10x=33

-7x+82=33

-7x=33-82

-7x=-49 cut the negative signs as its LHS and RHS

x=49/7=7

b)-5x+3(3x-3)=3 as y=3x-3 is given

-5x+9x-9=3

4x-9=3

4x=3+9

x=12/4=3

c)4x+11-5x=9

-x+11=9

-x=9-11

-x=-2 cut the negative signs as its LHS and RHS

x=2

d) 5y+ -5-2y=-11 as x=-5-2y is given

3y+-5=-11

3y=-11+5

3y=-6

y=-6/3=-2

e)-5x-4(2x+1)=35 as y=2x+1

-5x-8x+4=35

3x+4=35

3x=35-4

3x=31

x=31/3

x=10.3

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Building a is 271 meters taller than building

kvv77 [185]

Let a and b represent the heights of the corresponding buildings (in meters).

... a = b +271 . . . . . . . a is 271 meters taller than b

... 2b -a = 211 . . . . . . if a is subtracted from twice b, the result is 211

Use the expression for a in the first equation to substitute for a in the second.

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3 years ago

Mrs. lama marked a price of a cosmetic item 25% above it's cost price. if the cost price of the cosmetic item was 4400, at what

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2 years ago

For which pair of functions is the vertex of k(x)7 units below the vertex of f(x)?

kvv77 [185]

Answer: Option C

$f(x) = x^2;\ k (x) = x ^ 2 -7$

Step-by-step explanation:

Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:

$k (x) = f (x) + b$

If $b> 0$ then the graph of k(x) will be the graph of f(x) displaced vertically b units down.

If $b> 0$ then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.

In this case we have

$f (x) = x ^ 2$

We know that this function has its vertex in point (0,0).

Then, to move its vertex 7 units down we apply the transformation:

$k (x) = f (x) - 7\\\\k (x) = x ^ 2 -7$ .

Then the function k(x) that will have its vertex 7 units below f(x) is

$k (x) = x ^ 2 -7$

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